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nata0808 [166]
3 years ago
8

Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
-2x + 6y = -34
-x + 3y = -17
x = 3y +17

Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)

Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)
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antiseptic1488 [7]

Answer:

z=-4

Step-by-step explanation:

Simplify 10 + 2z + 2z to 10 + 4z

Add 10 to both sides

Simplify 10 + 4z + 10 to 4z + 20

Subtract 4z from both sides

Simplify -z - 4z − z− 4z to -5z − 5z.

Divide both sides by -5 − 5

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Step-by-step explanation:

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One of the legs of a right triangle measures 13 cm and the other leg measures 1 cm. Find the measure of the hypotenuse. If neces
velikii [3]

Answer:

hypotenuse = 13.0 cm

Step-by-step explanation:

Given the dimensions of a right triangle whose legs have measures of 13 cm and 1 cm, we can use the Pythagorean Theorem to find the measure of the triangle's hypotenuse.

The <u>Pythagorean Theorem</u> states that the squared measure of a right triangle's hypotenuse is equal to the sum of the squared lengths of its legs. In other words:

Pythagorean Theorem:   c² = a² + b²

Let c = hypotenuse

     a  =  Leg₁   = 1 cm

    b  =  Leg₂  =  13 cm

Substitute these values into the given formula to find the measure of the hypotenuse, c:

c² = a² + b²

c² = ( 1 )² + (13)²

c² = 1 + 169

c² = 170

Next, take the square root of c² and 170 to isolate c:

\displaystyle\mathsf{\sqrt{c^2}\:=\:\sqrt{170}}

c = 13.04 or 13.0 cm

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3 years ago
formula is given along with the values of all but one of the variable. Find the value of the variable that is not given. Use 3.1
dalvyx [7]

Answer:

P = 20.

Step-by-step explanation:

Given that:

  • P= 2L +2W
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the variable that is not given is P. So to find out P, we substitute the two given values into the equation as following:

      P= 2L + 2W

<=> P = 2(6) + 2(4)

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<=> P = 20.

Hope it will find you well.

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3 years ago
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The picture is blurry for me :/
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