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cupoosta [38]
3 years ago
7

To determine the mechanical advantage of a wedge, you divide the length of the slope by the __________________.

Physics
2 answers:
goldfiish [28.3K]3 years ago
8 0
You need to have the right thickness

Crank3 years ago
3 0
I think its c hope it helps
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How long will it take an object to hit the ground if dropped from 100 meters
mash [69]

Answer:

The answer depends on what object you are dropping. Are you dropping a balloon or a car? (I'm joking 'bout that one.) If the mass of the object is very little, then it might drop slower. If the mass is bigger, then it might drop faster.

Good luck!

Explanation:

8 0
3 years ago
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A force of 50 newtons causes a sled to accelerate at a rate of 5 meters per second. What is the mass of the sled.
notka56 [123]
F=ma
50=m(5)
m=10kg
hence,ans is B
5 0
3 years ago
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What is the Sl unit for speed
Akimi4 [234]

Answer: meter per second

Explanation: meter per second

Speed has the dimensions of distance divided by time. The SI unit of speed is the meter per second, but the most common unit of speed in everyday usage is the kilometer per hour or, in the US and the UK, miles per hour. For air and marine travel the knot is commonly used.

3 0
3 years ago
Dona rolls a marble with a speed of 5.0/m/s across a level table that is 1.6m above the floor. Upon reaching the edge of the tab
san4es73 [151]

Answer:

2.9 m

Explanation:

First find the time it takes to reach the floor.

y = y₀ + v₀ t + ½ at²

(0 m) = (1.6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.571 s

Next, find the distance it travels in that time.

x = x₀ + v₀ t + ½ at²

x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²

x = 2.86 m

Rounded to two significant figures, the marble travels 2.9 meters in the x direction.

5 0
3 years ago
We are sending a 30 Mbit file from source host A to destination host B. All links in the path between source and destination hav
Dmitrij [34]

Answer:

t=1.5\times 10^{-4}\ s

Explanation:

Given:

  • file size to be transmitted, D=30\ Mb
  • transmission rate of data, \dot D=10\ Mb.s^{-1}
  • propagation speed, v=2\times 10^8\ m.s^{-1}
  • distance of data transfer, s=10000\ km=10^4\ m

<u>Now the delay in data transfer from source to destination for each 10 Mb:</u>

t'=\frac{s}{v}

t'=\frac{10^4}{2\times 10^8}

t'=5\times 10^{-5}\ s

<u>Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:</u>

So,

t=3\times t'

t=3\times 5\times 10^{-5}

t=1.5\times 10^{-4}\ s

3 0
3 years ago
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