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GREYUIT [131]
2 years ago
12

Can you solve the issue

Physics
1 answer:
loris [4]2 years ago
3 0

Answer:

The answer is  271.3 joules .

Explanation:

          Work = (weight) x (distance)

 Work = (50 lb) x (1 kg / 2.20462 lb) x (9.81 newton/kg)

                          x (4 feet) x (1 meter / 3.28084 feet)

          = (50 x 9.81 x 4) / (2.20462 x 3.28084)  newton-meter

          =        271.3 joules .

We don't need to know how long the lift took, unless we

want to know how much power he was able to deliver.

                  Power = (work) / (time)    

                              = (271.3 joule) / (5 sec)  =  54.3 watts .

________________________________________

The easy way:

        Work = (weight) x (distance)

                  = (50 pounds) x (4 feet)  =  200 foot-pounds

Look up (online) how many joules there are in 1 foot-pound.

There are  1.356 joules in 1 foot-pound.

So  200 foot-pounds = (200 x 1.356) = 271.2 joules.

credits original answer AL2006

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A moving particle encounters an external electric field that decreases its kinetic energy from 9520 eV to 7060 eV as the particl
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Given Information:

KEa = 9520 eV

KEb = 7060 eV

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Required Information:

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