A boy throws a steel ball straight up. consider the motion of the ball only after it has left the boy's hand but before it touch
2 answers:
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Answer:
at x=0
=W*L/L
and
=W-
Explanation:
Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.
moments is the product of force and the perpendicular distance in line of the action of the given force
from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.
also, sum of upward forces must be equal to sum of downward forces
Going by the aforementioned,
taking moments about
W*(l-x)=*(L)
=W*(L-x)/(L)..............1
at x=0
=W*L/L
also
+
=W
=W-
To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,
Here,
= Permeability free space
I = Current
L = Length
d= Distance between them
Our values are,
Rearranging the previous equation to find the current,
Therefore the current in the rods is 210.6A