Answer:
Part a)
Part b)
Part c)
Part d)
Explanation:
Part a)
For hanger we know that it will have tension force upwards while it has downwards its weight so we will have
so we have
Part b)
now for car that is rolling on the floor the net force is given as
Part c)
now we know that the cart and the hanger both are connected to each other
so they must have same acceleration
so we will have
Part d)
now we know that
M = 2.40 kg
m = 0.50 kg
so we will have
Answer:
potential enrgy U = m g L sin θ
speed V = √(2g L sin θ)
Explanation:
The expression for the gravitational potential energy of a body is
U = mg Y - mg Yo
Where Y give us a constant initial energy from which the differences are measured, for general simplicity it is selected as zero, Yo= 0
What we find an expression for height, let's use trigonometry
sin θ= Y / L
Y = l sin θ
We substitute in the power energy equation
U = m g L sin θ
2. The mechanical energy of the system is conserved, so we will write the mechanical energy at two points the highest and the lowest
Highest Em = U
Lower Em = K
U = K
m g L sin θ = ½ m v²
V = √(2g L sin θ)
Answer:
1. Examples of transverse waves include vibrations on a string and ripples on the surface of water. We can make a horizontal transverse wave by moving the slinky vertically up and down. In a longitudinal wave the particles are displaced parallel to the direction the wave travels.
2. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. The animations below demonstrate both types of wave and illustrate the difference between the motion of the wave and the motion of the particles in the medium through which the wave is travelling.
3. f is force and 人 is wave length
Answer:
0.001 s
Explanation:
The force applied on an object is equal to the rate of change of momentum of the object:
where
F is the force applied
is the change in momentum
is the time interval
The change in momentum can be written as
where
m is the mass
v is the final velocity
u is the initial velocity
So the original equation can be written as
In this problem:
m = 5 kg is the mass of the fist
u = 9 m/s is the initial velocity
v = 0 is the final velocity
F = -45,000 N is the force applied (negative because its direction is opposite to the motion)
Therefore, we can re-arrange the equation to solve for the time:
