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adell [148]
3 years ago
14

It's possible to build a triangle with side lengths of 3, 3, and 9.

Mathematics
1 answer:
cestrela7 [59]3 years ago
6 0

Answer: No.

Good luck! I hope this is right!

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Give one example of when you would. use the friendly numbers strategy to subtract .Explain why ?
lord [1]
Say you were solving 27 + 19. If you were planning on using the friendly numbers strategy, you'd look at the first <span>addend, 27, and determine that</span> the closest "friendly number" here is thirty, which you'd get by adding 3. From there, you can jump to the next friendly number, forty, by adding another 10. So far you'd've added 13, and you'd need another 6 for that too add up to 19, your second addend. After adding 3, 10, and 6 to 27, you'd find your sum, or "final answer"- 46.

I hope this was what you were looking for!
5 0
4 years ago
PLEASE HURRY!! 30 POINTS<br><br> simplify<br><br> 7/3+3(2/3−1/3)^2
11Alexandr11 [23.1K]
<span>7/3+3(2/3−1/3)^2
= 7/3 + 3(1/3)^2
= 7/3 + 3(1/9)
= 7/3 +1/3
= 8/3</span>
8 0
4 years ago
Read 2 more answers
400 grams = 480 ml<br> so,<br> 180 grams = ?
Viefleur [7K]

Answer: 216 ml

Step-by-step explanation:

400 grams = 480 ml

180 grams = ?

Since the value of 180 grams in milliliters is unknown, let the unknown be Z

Thus, 400 grams = 480 ml

180 grams = Z

To get the value of Z, cross multiply

Then, Z x 400 grams = 480ml x 180 grams

400Z = 86400

Divide both sides by 400

400Z/400 = 86400/400

Z = 216

Thus, 180 grams is equal to 216 milliliters.

5 0
3 years ago
Read 2 more answers
What is the value of 5 to the power of 4 over 5 to the power of 6?
Pani-rosa [81]
\dfrac{5^4}{5^6}=\dfrac{5\cdot5\cdot5\cdot5}{5\cdot5\cdot5\cdot5\cdot5\cdot5}\\\\=\dfrac{\not5\cdot\not5\cdot\not5\cdot\not5}{\not5\cdot\not5\cdot\not5\cdot\not5\cdot5\cdot5}=\dfrac{1}{5\cdot5}=\dfrac{1}{25}

Use:\ \dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^4}{5^6}=5^{4-6}=5^{-2}=\dfrac{1}{5^2}=\dfrac{1}{25}
5 0
4 years ago
DEFG is a rhombus with m∠EFG=28. What is m∠FGE?<br> 76<br> 152<br> 14
Katen [24]
14 adverage between numbers but i might be wrong
3 0
3 years ago
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