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TEA [102]
3 years ago
8

Help me please !!

Mathematics
2 answers:
kykrilka [37]3 years ago
6 0

The number is 12.531880149. This number is not rational

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hope it helps

Vedmedyk [2.9K]3 years ago
3 0

Answer:

A rational number an irrational number a whole number

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Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6
Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

5 0
3 years ago
I'll give brainlliest to whoever anwsers
postnew [5]

Answer:

Step-by-step explanation:

booom

8 0
3 years ago
If your getting paid 5$ every week how long will it takes you to get 10,000$?
nikdorinn [45]
2,000
10,000 divided by 5 = 2,000
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2 years ago
Which of the following points are solutions to the inequality below?
Helga [31]
The inequality :y ≥ 2 x - 1We shall plug-in all the values:A ) - 3 ≥ 6 - 1- 3 ≥ 5    ⊥  ( not correct )
B ) - 5 ≥ 4 - 1- 5 ≥ 3   ⊥C ) - 5 ≥ 6 - 1- 5 ≥ 5   ⊥D ) 0 ≥ 0 - 10 ≥ - 1    T  ( correct )E ) - 8 ≥ 10 - 1- 8 ≥ 9   ⊥F ) - 9 ≥ 10 - 1- 9 ≥ 9   ⊥Answer: D )   ( 0, 0 ).

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3 years ago
Read 2 more answers
Help with this math question
Ulleksa [173]

Answer:

-\frac{13\sqrt{x} }{x}

Step-by-step explanation:

We have been given the following expression;

-13/√x

In order to rationalize the denominator, we multiply the numerator and the denominator by √x;

-\frac{13}{\sqrt{x}}=-\frac{13\sqrt{x} }{\sqrt{x}\sqrt{x}}\\ \\-\frac{13\sqrt{x} }{\sqrt{x^{2} } }\\\\-\frac{13\sqrt{x} }{x}

6 0
3 years ago
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