-4 is also a geometric mean
if we consider a(first element in series)=1 and r(common ratio)=-4 then the series would be
1,-4,16,-64,256,…..,a(-4)^(n-1 )
where n is nth term
from this -4 would be the geometric mean if we consider -4 as common ratio .
If we consider 4 as common ratio then geometric mean should be 4
so you should mention whether common ratio >0 or not (r>0 or not) .
[without ‘r’ value you can’t solve the question but in general most of the teachers will consider r>0.]
So, -4 won’t be geometric mean of 1 & 16
A. 5
B. -3/1
C. Negative
D. You have to go down 3 over to the right one from where your y-intercept is.
To plot the y intercept plot (0,5)
To plot the next point go down 3 over 1 to the right from the y-ing
Step-by-step explanation:
part A:
part B:
![Area_{_{surface}}=3.14*(15+9)=3.14*24=75.36[units^2].](https://tex.z-dn.net/?f=Area_%7B_%7Bsurface%7D%7D%3D3.14%2A%2815%2B9%29%3D3.14%2A24%3D75.36%5Bunits%5E2%5D.)
Answer:
i think it is 1.127
Step-by-step explanation:
