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2 years ago

I don't know what to do

Mathematics

1 answer:

anyanavicka [17]2 years ago

8 0

If you don't..I don't either by answering your question...

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For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12

sleet_krkn [62]

Answer: p = 6

Step-by-step explanation:

HI !

px + 3y - ( p-3)=0

a₁ = p , b₁ = 3 , c₁ = - (p-3)

=====================

12x + py - p=0

a₂ = 12 , b₂ = p , c₂ = -p

since , the equations have infinite solutions ,

a₁/a₂ = b₁/b₂ = c₁/c₂

p/12 = 3/p = p-3/p

--------------------------------------

p/12 = 3/p

cross multiply ,

p² = 36

p = √36

p = 6

for the value of p = 6 , the equations will have infinitely many solutions

5 0

2 years ago

Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m

Molodets [167]

Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

The limit of a constant is the constant.

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

8 0

2 years ago

Y+7=-2(x-1)<br><br><br> hurry plz

zhannawk [14.2K]

Answer:

y=-2x-5

Step-by-step explanation:

First of all, you have to distribute -2 to (x-1) to get to this equation y+7=-2x+2. Then, you subtract 7 on both sides to get the slope-intercept of y = -2x - 5.

8 0

2 years ago

True or False, In Euclidean geometry, there is only one equilateral triangle

docker41 [41]

True, In Euclidean geometry an equilateral triangle must be a 60-60-60 triangle.

Hope This Helps!!!

5 0

3 years ago

pls help no one will how do estimate the numbers im about to give you by rounding to the nearest integer 15.23 - 6.835 and 6.88

gayaneshka [121]

I think it's just 15, -7, 7, -8, and 80.
I am probably wrong though,
Is it all one long equation with the plus and minus signs?

8 0

2 years ago