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3 years ago

A cable installer charges $45.00 per hour

Mathematics

2 answers:

Anastaziya [24]3 years ago

6 0

Answer:

60.0 + 45.0 x h

Step-by-step explanation:

Leona [35]3 years ago

4 0

Answer:

c(h)=45h+60

Step-by-step explanation:

h= hours worked

b=baseline service charge.

x= hourly fee

c(h)=xh+b

Plug in known values.

c(h)=45h+60

You might be interested in

Is 9.99 rational or irrational

aleksley [76]

Answer:

Rational

Step-by-step explanation:

A rational number can be written as a fraction of the form.

$\frac{a}{b} \: where \: b \ne0$

and a and b are integers.

$9.99 = \frac{999}{100}$

Hence in this case a=999 and b=100.

Since both are integers with b being a non-zero integer, we conclude that 9.99 is a rational number.

6 0

3 years ago

Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!

Nadya [2.5K]

QUESTION 1

If a function is continuous at $x=a$ , then $\lim_{x \to a}f(x)=f(a)$

Let us find the limit first,

$\lim_{x \to 4} \frac{x-4}{x+5}$

As $x \rightarrow 4$ , $x-4 \rightarrow 0$ , $x+5 \rightarrow 9$ and $f(x) \rightarrow \frac{0}{9}=0$

$\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0$

Let us now find the functional value at $x=4$

$f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0$

Since

$\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4)$ , the function is continuous at $a=4$ .

QUESTION 2

The correct answer is table 2. See attachment.

In this table the values of x approaches zero from both sides.

This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.

The values are also very close to zero unlike those in table 4.

The correct answer is B

QUESTION 3

We want to evaluate;

$\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}$

using the properties of limits.

A direct evaluation gives $\frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}$ .

This indeterminate form suggests that, we simplify the function first.

We factor to obtain,

$\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}$

We cancel common factors to get,

$\lim_{x \to 1} (x+3)^2$

$=(1+3)^2=16$

The correct answer is D

QUESTION 4

We can see from the table that as x approaches $-2$ from both sides, the function approaches $-4$

Hence the limit is $-4$ .

See attachment

The correct answer is option A

3 0

3 years ago

In a kite ABCD, AB=AD, BC=CD; CAD=40° and

notka56 [123]

Answer: See below

Step-by-step explanation:

From the figure attached below,

We know that by the SSS property, the two triangles are congruent

$Since,$$\begin{aligned}&A D=A B(\text {Given}) \\&C D=B C(\text {Given}) \\&A C=A C \text { (Common side})\end{aligned}$$Hence,$$\triangle A B C \cong \triangle A C D$$By the properties of congruence,$$\angle O A D=\angle O A B=40^{\circ}$$$$\angle B=\angle D$

Using the property of congruence to find the measure of all these angles:

Therefore, the measure of the angles are:

$&a) \ B\widehat{ A} C=40^{\circ} \\ b) \ &B\widehat{C}A=180^{\circ}-\left(90^{\circ}+60^{\circ}\right)=30^{\circ} \\c) \ &A \widehat{D} C=60^{\circ}+50^{\circ}=110^{\circ}$