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3 years ago

Sort these elements into pairs Mg Cl As Sr I N

Chemistry

2 answers:

o-na [289]3 years ago

7 0

Metal goes with the non-metal

LenKa [72]3 years ago

4 0

Metals:-

Mg(Magnesium)

Sr(Strontium)

Non-metals are:-

Cl(Chlorine)

I(Iodine)

N(Nitrogen)

Metalloids are:-

As(Arsenic)

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2.41 x 10^2 Cm to meters

Assoli18 [71]

We know that there are 100 cm in 1 m, so we can use this to convert to meters:

$(\frac{2.41x10^{2}cm}{1})*(\frac{1m}{100cm} )=2.41m$

Therefore we know that $2.41x10^{2}$ cm is equal to 2.41 m.

8 0

3 years ago

Read 2 more answers

A 59.1g sample of aluminum is put into a calorimeter (see sketch at right) that contains 250.0g of water. The aluminum sample st

Rainbow [258]

Answer:

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

Explanation:

Step 1: Data given

Mass of aluminium = 59.1 grams

Mass of water = 250.0 grams

Initial temperature of aluminium = 91.3 °C

Initial temperature of water = 16.0 °C

Final temperature = 19.5 °C

Pressure remains constant

Specific heat capacity of water = 4.186 J/g°C

Step 2: Calculate specific heat of aluminium

Heat lost = heat gained

Qlost = -Q heat

Q = m*c*ΔT

heat aluminium = - heat water

m(aluminium) * c(aluminium) * ΔT(aluminium) = -m(water) * c(water) * ΔT(water)

⇒m(aluminium) = mass of aluminium = 59.1 grams

⇒c(aluminium) = the specific heat of aluminium = TO BE DETERMINED

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 91.3 = -71.8 °C

⇒ m(water) = 250.0 grams

⇒c(water) = the specific heat of water = 4.186 J/g°C

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 16.0 = 3.5 °C

59.1 * c(aluminium) * -71.8 °C = 250.0 * 4.186 J/g°C * 3.5 °C

c(aluminium) = 0.863 J/g°C

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

3 0

3 years ago

When NH NO3(aq) reacts to form N2O(g) and H2O(1), 150 kJ of energy are evolved for each mole of NH NO3(aq) that reacts.

amid [387]

Billy bobbbbbbbbbbbbbbbbbbbbbbb

4 0

3 years ago

A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch

amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0

3 years ago

In everyday speech the words precision and accuracy are often used interchangeably. When these terms are used in science are the

padilas [110]

Answer:

No, in science their meanings are not the same as their everyday meanings.

Explanation:

In Science, Precision and Accuracy are defined as,

Accuracy:

Accuracy is the value which is closest to the known or standard value.

Precision:

While, Precision is the value of closeness of two measured values to each other.

Example:

Let suppose in Chemistry Lab you weight an object as 50 g. While the actual weight of that object is 30 g. It means your reading is not accurate.

On second measurement you find that the object weight is 31 g. This time your reading is not precise.

3 0

4 years ago