Science investigation skills

1 answer:

8 0

People conduct scientific investigations by formulating a hypothesis and observing the results. They then draw conclusions from those results and then share those conclusions with the larger scientific community.

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Which of the following shows 3x + 15 + 6x – 7 + y in simplest terms?

prisoha [69]

Answer:

9x+y+8

Explanation:

We know this because you add 3x and 6x to get 9x

then we only have one y so put y by itself then subtract 15 and y which gets us 8

3 0

4 years ago

Calculate the mass of sodiumtetraoxosulphatevi formed when 5garms of sodiumhydroxide react with tetroxosulphatevi acid

rewona [7]

Answer: 8.88g

Explanation:Please see attachment for explanation

4 0

3 years ago

What is the condition of water in the hydrosphere right now?

SCORPION-xisa [38]

Answer:

A planet's hydrosphere can be liquid, vapor, or ice. On Earth, in the places at the north and south pole, water exists in ice or glacier form, in the atmosphere it exists in vapor form and liquid water exists on the surface in the form of oceans, lakes and rivers. It also exists below ground as groundwater, in wells and aquifers. Water collects in clouds, then falls to Earth in the form of rain or snow,

Hope it helps

:D

6 0

4 years ago

6.50 g of a certain Compound x, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1

gayaneshka [121]

Answer:

$C_{10}H_8$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:

$n_C=22.35gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.51molC\\\\m_C=0.51molC*\frac{12.01gC}{1molC} =6.10gC$

$n_H=3.66gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.41molH\\\\m_H=0.41molH*\frac{1.01gH}{1molH}=0.41g$

Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:

$C:\frac{0.51mol}{0.41mol}= 1.24\\\\H:\frac{0.51mol}{0.51mol}= 1\\\\C_{1.24}H$