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1 year ago

19. A girl has four skirts and six blouses. How many different skirt-blouse combiNtions can she wear?

Mathematics

1 answer:

cupoosta [38]1 year ago

7 0

4 combinations of skirt blouses

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The area of a rectangle is 60 cm2 If the width of the

aleksklad [387]

The length of the rectangle is 10 cm and perimeter of the rectangle is 32 cm.

Step-by-step explanation:

Given,

The area of rectangle = 60 sq cm

Width (b) of the rectangle = 6 cm

To find the length and perimeter of the rectangle.

Formula

The area of the rectangle = l×b

The perimeter of the rectangle = 2(l+b)

According to the problem,

l×b = 60

or, l×6 = 60

or, l = 60÷6 = 10

Length (l) = 10 cm

Perimeter = 2×(10+6) cm = 32 cm

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3 years ago

Scientific Notation:<br> what’s (2.2 x 10 to the -4) - (3 x 10 to the 2)

Marrrta [24]

Answer:

$2.23\times10^4$

Step-by-step explanation:

In order to get the answer to this question you need to turn the scientific notations into standard form then subtract the two standard forms.

$(2.2\times10^{-4})-(3\times10^2)$

Turn the notations into standard form:

$2.2\times10^{-4} = .00022$

$3\times10^2=300$

$.00022-300=22300$

$=22300$

Turn into notation form:

$22300 = 2.23\times10^{4}$

Hope this helps.

8 0

2 years ago

Sasha buys two ribbons of equal length. She cuts 9 pieces of the same length, L, from the first ribbon and finds that 5 inches a

nikitadnepr [17]

Answer:

50 inches.

Step-by-step explanation:

Let the length of the each ribbon was x.

Now, she cuts 9 pieces of same length L which means total length is 9L.

Now, doing the same she was left with 5 inches of ribbon. Hence, we have

[tex[9L+5=x.....(1)[/tex]

Similarly, we can write a equation for the second situation.

$2L+40=x......(2)$

From equation 1 and 2,

$9L+5=2L+40\\\\7L=35\\\\L=5$

Plugging this value in equation 1,

$9(5)+5=x\\\\x=45+5\\x=50$

Therefore, the length of each ribbon when she bought them was 50 inches.

3 0

3 years ago

3x2=7 5x4=23 7x6=47 9x8=79 10x9=?

Mashcka [7]

$(a\times b) = (a\times b) +(b -1) = c \\ \\ 3 \times 2 = (3\times 2) +(2-1) = 6 +1=7 \\ \\ 5 \times 4 = (5\times 4) +(4-1) = 20 +3=23 \\ \\ 7 \times 6 = (7\times 6) +(6-1) = 42 +5=47 \\ \\ 9 \times 8= (9\times 8) +(8-1) = 72 +7=79 \\ \\ \\ \\ 10 \times 9 = (10\times 9) +(9-1) = 90 +8=\boxed {\bf{98}}\\\sf {10\times 9 = \boxed{\bf {98}}}$