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UNO [17]
2 years ago
10

19. A girl has four skirts and six blouses. How many different skirt-blouse combiNtions can she wear?

Mathematics
1 answer:
cupoosta [38]2 years ago
7 0
4 combinations of skirt blouses
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The diagram below shows a wall with a
yulyashka [42]

Answer:  H (131.125 ft^2)

Step-by-step explanation:

first, you need to find the area of the wall

wall:

A=Lw  (length times width)

A= 9.75 x 15.5  (I changed them into decimals)

A = 151.125

now you need to find the area of the window

window:

A = Lw

A = 4 x 5

A = 20

now you need to subtract the area of the window from the area of the wall to find the amount of space you need to cover with wallpaper

151.125 - 20 = 131.125

6 0
4 years ago
Pin this please answer my question i will make you a brainlist .....​
cricket20 [7]

Answer:

  • 10%

Step-by-step explanation:

<u>Given:</u>

  • Borrowed amount P = Rs 100000
  • Time t = 3 years
  • Number of compounds n = 3
  • Interest I = Rs 33100
  • Rate r = ?

<u>Use formula:</u>

  • I = P(1 + r)³ - P

<u>Substitute values and solve for r:</u>

  • 33100 = 100000(1 + r)³ - 100000
  • 133100 = 100000(1 + r)³
  • (1 + r)³ = 133100/100000
  • (1 + r)³ = 1.331
  • 1 + r = ∛1.331
  • 1 + r = 1.1
  • r = 0.1  or 10%
5 0
3 years ago
Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!
lawyer [7]
Your answer is C. 3 units left and 2 units up. This is because this distance between 1 and -2 is 3 units, and the distance between 3 and 5 is 2 units. The scale factor would be 1.75, because 7 ÷ 4 = 1.75
I hope this helps
8 0
3 years ago
identify the vertex of the following function and state of it is a minimum or maximum f(x)= 2(x-3)2+ 2
Alinara [238K]

Answer:

vertex = (3, 2)

minimum

Step-by-step explanation:

6 0
3 years ago
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