Answer:
Explanation:
Resistance of the tungsten wire
R = resistivity x length / cross sectional area
= 
= 107 x 10⁻⁴ ohm
Resistance at 120 degree can be obtained from the following formula
= 155.15 x 10⁻⁴ ohm
= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )
current = 12.5
potential diff = 12.5 x 155.15 x 10⁻⁴ V
= 0 .1939 V
= .19 V
required electric field = potential diff / length of wire
= .1939 / 16 x 10⁻²
= 1.2 N / C
Answer:
In hot gases , the atoms keeps colliding with each other and sometimes the energy liberated during collision takes the electron to a higher level,thus, .The object is a cloud of hot gas and finally the electron returns back emitting photon
The victim's head is accelerated faster and harder than the
torso when the victom is involved in a typical rear-end collision.
The traffic accident where a vehicle crashes into another
vehicle that is directly in front of it is called a rear-end collision.
One of the most common accident in the United States is the
rear-end collision, and in a lot of cases, rear-end collisions are prompted by
drivers who are inattentive, unfavorable conditions of the road, and poor
following distance.
<span>An enough room in front of your car so you can stop when the
car in front of you stops suddenly is one basic driving rule. The person isn’t
driving safely if he / she is behind you and couldn’t stop.</span>
Missing question: "<span>What is the magnitude of the impulse I imparted to the clay by the floor during the impact?"
Solution:
The impulse is equal to the variation of momentum of the object:
</span>
<span>where m is the mass of the object and </span>
is the variation of velocity of the object during the impact.
By using energy conservation, we can calculate the velocity of the object before the impact. In fact, the initial potential energy of the object is all converted into kinetic energy before the impact:
from which we find v:
This is the velocity of the object just before the impact. After the impact, the object comes to rest: this means that the variation of velocity of the object is equal to 4.75 m/s. Therefore, the impulse is
