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Rus_ich [418]
3 years ago
13

In a typical rear-end collision, the victim's ________ is/are accelerated faster and harder than the torso

Physics
2 answers:
Georgia [21]3 years ago
8 0

The victim's head is accelerated faster and harder than the torso when the victom is involved in a typical rear-end collision.

The traffic accident where a vehicle crashes into another vehicle that is directly in front of it is called a rear-end collision.

 

One of the most common accident in the United States is the rear-end collision, and in a lot of cases, rear-end collisions are prompted by drivers who are inattentive, unfavorable conditions of the road, and poor following distance.

 

<span>An enough room in front of your car so you can stop when the car in front of you stops suddenly is one basic driving rule. The person isn’t driving safely if he / she is behind you and couldn’t stop.</span>

Makovka662 [10]3 years ago
5 0

Answer:

In a typical rear-end collision, the victim's head is accelerated faster and harder than the torso

Explanation:

In a collision the body part most at risk of injury is the head. This is because the victim's torso is secured with the seat belt, so at the moment of collision the torso is held by the belt and prevented from reaching a speed compatible with the collision. However, there is no device that holds the victim's head, so at the moment of collision, the victim's head will be accelerated faster and stronger than the torso.

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Norma-Jean [14]
The power of the antenna is
P=1.00 kW=1000 W
and since the power is the emitted energy divided by the time, the energy emitted per second is
E=Pt = (1000 W)(1 s)=1000 J

The frequency of the emitted photons is
f=2515 MHz=2.515 \cdot 10^9 Hz
So the energy of a single photon is
E_1=hf=(6.6 \cdot 10^{-34} Js)(2.515 \cdot 10^9 Hz)=1.66 \cdot 10^{-24} J

Therefore, to find the number of emitted photons per second, we should divide the total energy emitted by the antenna in 1 second by the energy of a single photon:
N= \frac{E}{E_1}= \frac{1000 J}{1.66 \cdot 10^{-24} J}=  6.02 \cdot 10^{26}
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Given that

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--------

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