An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
<h3>What is mechanical energy?</h3>
Mechanical energy is the sum of potential energy and kinetic energy.
Total mechanical energy = P.E max = K.E max
Total mechanical energy = K.E +P.E
Given is the kinetic energy is (3/4)E.
E= (3/4)E + P.E
P.E = (1/4) E
Maximum potential energy =E = (1/2) k A²
Here. A is the maximum displacement and k is the spring constant.
The potential energy at kinetic energy of (3/4) E is
P.E = (1/4)E = (1/8) k A²
Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
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Answer:
1.46× 10^-8 N
Explanation:
F=Gm₁m₂/r²
F=(6.67×10⁻¹¹ × 50× 70)/(4)²
F=1.46× 10^-8 N
Hope, this helps you.
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:

Using

and

, we can find the value of the force applied to the roller-blade to obtain this acceleration:
469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.
This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.
The equation of components on the x axis.
, where x is the distance and Vox the initial velocity before the drop
The equation of components on the y axis.
, where y is the height, and the velocity in y component before the drop is 0, reducing the equation to 
Clear t from both the equation of components on the x axis and the y axis:
and 
Equating both equations and clearing the distance x:

Substituting the values:
