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3 years ago

Explain with method pls..

Physics

1 answer:

seraphim [82]3 years ago

5 0

Answer:

See explanation below.

Explanation:

Given two blocks of masses M and m, And a force F acting on the block of mass M pulling it outside.

The two masses system can be considered as a whole, With F being the only external force acting on them.

Here the spring force has been ignored as while considering the two system as a whole, it will be accounted as an internal force for the system

Therefore, The acceleration of the system will be:

$a=\frac{Total\:external\:force}{Total\:mass}=\frac{F}{m+M}$

Now both the masses are moving with this same acceleration towards the direction of force .

Acceleration of mass m = a (as the system is moving as a whole)

Force on the mass m= mass times acceleration.

$Force=ma=\frac{mF}{m+M}$

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An object of height 2.2 cm is placed 5.1 cm in front of a diverging lens of focal length 19 cm and is observed through the lens

monitta

Answer:

a) i = -4.02 cm , b) h’= 1,576 cm

Explanation:

a) The constructor equation is

1 / f = 1 / i + 1 / o

Where f is the focal length, i and o are the distance to the image and the object

Let's clear the distance to the image

1 / i = 1 / f - 1 / o

1 / i = 1 / -19 - 1 / 5.1

1 / i = 0.2487

i = -4.02 cm

b) let's use the expression of magnification

m = h’/ h = - i / o

h’= - h i / o

h’= 2.2 4.02 /5.1

h’= 1,576 cm

3 0

3 years ago

Assuming no air resistance, how far will a 0.0010 kg raindrop have fallen when it hits the ground 30.0 s later. Assume g = 9.8 m

Serga [27]

D = (1/2)·at²
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d = (1/2)·(9.8 m/s²)·(30 s)² = (1/2)·(9.8)·(900) m
d = 4410 m
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6 0

3 years ago

Read 2 more answers

A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.

Aleonysh [2.5K]

Answer: $53.31\°$ East of North

Explanation:

We have the following data:

Speed of the wind from East to West: $6.68 m/s$

Speed of the bee relative to the air: $8.33 m/s$

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the Speed of the wind from East to West (in the horintal part) and the speed due North relative to the ground (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

$sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}$

$sin \theta=\frac{6.68 m/s}{8.33 m/s}$

Clearing $\theta$ :

$\theta=sin^{-1} (\frac{6.68 m/s}{8.33 m/s})$

$\theta=53.31\°$

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3 years ago

Question 30

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