Question

What's the value of x to the nearest tenth? Question 12 options: A) 7.9 B) 9.7 C) 5.9 D) 8.1

Answer 1

Answer:

The value is 9.7

Step-by-step explanation:

Use the Pythagorean theorem. $a^{2} + b^{2}= c^{2}$

a=7 b=x c=12

$7^{2} + x^{2}= 12^{2}$

$49+x^{2} =144$

$144-49=95$

$x^{2} =95$

$\sqrt{ x^{2}} =\sqrt{95}$

x=9.74679434481

x=9.7