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3 years ago

How many moles are in 19.6 g of Sodium (Na)? And the conversion factor?

Chemistry

1 answer:

Snezhnost [94]3 years ago

6 0

Answer:

n=0.852 moles

Explanation:

Given mass is, m = 19.6 g

The molar mass of sodium is, M = 22.99 u

We need to find the no of moles in 19.6 of Sodium. We know that, no of moles is equal to given mass divided by molar mass.

$n=\dfrac{m}{M}\\\\n=\dfrac{19.6}{22.99}\\\\n=0.852$

So, there are 0.852 moles in 19.6 g of Sodium.

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What is the coefficient of silver in the final, balanced equation for this reaction?

katovenus [111]

Answer: 3

Explanation:

An oxide-reduction reaction or, simply, redox reaction, is a chemical reaction in which one or more electrons are transferred between the reactants, causing a change in their oxidation states, which is the hypothetical electric charge that the atom would have if all its links with different elements were 100% ionic.

For there to be a reduction-oxidation reaction, in the system there must be an element that yields electrons and another that accepts them:

The oxidizing agent picks up electrons and remains with a state of oxidation inferior to that which it had, that is, it is reduced.
The reducing agent supplies electrons from its chemical structure to the medium, increasing its oxidation state, ie, being oxidized.

To balance a redox equation you must identify the elements that are oxidized and reduced and the amount of electrons that they release or capture, respectively.

In the reaction that arises in the question the silver (Ag) is reduced because it decreases its oxidation state from +1 to 0 and the aluminum (Al) is oxidized because its oxidation state increases from 0 to +3, releasing 3 electrons (e⁻). Then we can raise two half-reactions:

Ag⁺ + e⁻ → Ag⁰

Al⁰ → Al⁺³ + 3e⁻

In order to obtain the balanced equation, we must multiply the first half-reaction by 3 so that, when both half-reactions are added, the electrons are canceled. In this way:

(Ag⁺ + e⁻ → Ag⁰ ) x3

Al⁰ → Al⁺³ + 3e⁻ +

-------------------------------------

3Ag⁺ + Al⁰ → 3Ag⁰ + Al⁺³

So, the coefficient of silver in the final balanced equation is 3.

5 0

3 years ago

How many moles are there in 135g of aluminum ?

dem82 [27]

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Aluminium, or 26.981538 grams.

6 0

3 years ago

Identify the atom provided. * Boron Phophorus Sulfer Aluminum

REY [17]

Answer:

3. I think the answer is Sulfer

3 0

3 years ago

An outdoor grill has a propane (C3H8) tank that holds 4.8 L of gas at a pressure of 5.5 atm. If all of the gas is transferred in

shtirl [24]

Answer: 0.176 atm

Explanation: Solution attached:

Use Boyle's Law to find the new pressure of the gas.

P1V1 = P2V2

Derive for P2

P2 = P1V1 / V2

= 5.5 atm ( 4.8 L ) / 150 L

= 0.176 atm

4 0

3 years ago

7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m

Anna [14]

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ $(n_{A}) = 1$

Mole ratio of the base, NaOH $(n_{B}) = 2$

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH $(M_{B}) = 0.505 M$

Volume of the acid, H₂SO₄ $(V_{A}) = 40 mL$

Molarity of the acid, H₂SO₄ $(M_{A}) = 0.505 M$

<h3>Volume of the base, NaOH $(V_{B})$ =? </h3>

$\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}$

Cross multiply

$0.505 * V_{B} = 20.2 * 2\\0.505 * V_{B} = 40.4$

Divide both side by 0.505

$V_{B} = \frac{40.4}{0.505}\\\\V_{B} = 80 mL$

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

$1000 mL = 1 dm^{3}\\\\Therefore,\\\\80 mL = \frac{80 mL * 1dm^{3}}{1000 mL}\\\\80 mL = 0.08dm^{3}$

Therefore, the volume of NaOH required is 0.08 dm³

Learn more: brainly.com/question/19053582

3 0

3 years ago