Answer:
83ºC
Explanation:
A bomb calorimeter is an instrument used to measure the heat that release or absorb a particular reaction.
The reaction of combustion of propane is:
C₃H₈ + 5O₂ → 3 CO₂ + 4 H₂O ΔH = -2222kJ/mol
<em>1 mole of propane release 2222kJ</em>
10.0g of propane (Molar mass: 44.1g/mol).
10.0g ₓ (1mol/ 44.1g) = <em>0.227 moles of C₃H₈</em>
If 1 mole of propane release 2222kJ, 0.227moles will release (Release because molar heat is < 0):
0.227 moles of C₃H₈ ₓ (2222kJ / mol) = 504kJ.
Our calorimeter has a constant of 8.0kJ/ºC, that means if there are released 8.0kJ, the bomb calorimeter will increase its temperature in 1ºC. As there are released 504kJ:
504kJ ₓ (1ºC / 8.0kJ) = 63ºC will increase the temperature in the bomb calorimeter.
As initial temperature was 20ºC, final temperature will be:
<h2>83ºC</h2>
Answer:
The cause of percent yield of reaction to be less than 100% are:
1. incomplete or competing reactions
2. loss of sample during recovery
Explanation:
Answer:
The answer to your question is V2 = 29.9 ml
Explanation:
Data
Volume 1 = V1 = 35 ml
Pressure 1 = P1 = 1 atm
Temperature 1 = T1 = 150°C
Volume 2 = V2 = ? ml
Pressure 2 = P2 = 2 atm
Temperature 2 = T2 = 450 °C
Process
1.- Convert temperature to °K
Temperature 1 = 150 + 273 = 423°K
Temperature 2 = 450 + 273 = 723°K
2.- Use the Combined gas law to find the volume
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (1 x 35 x 723) / (423 x 2)
-Simplification
V2 = 25305 / 846
-Result
V2 = 29.9 ml
In theory, all 3 can make
up each Sedimentary, Metamorphic, and Igneous rocks.
However, the progression of metamorphosis is really kind of
linear, and it is only possible to metamorphose a Metamorphic rock further, so
the answer to this question would be:
<span>Igneous and Metamorphic rocks</span>
Answer: 92 kg
Explanation:
because the rest of them are increasing weight or not changing at all and if you were to go to the moon you would weigh less
