Mind giving me help on this?? :0

What’s the square root of 13 to the nearest integer

Marianna [84]

Answer:

4

Step-by-step explanation:

First off, integers are Whole Numbers (1,2,3,4, etc), so we are rounding the answer to the nearest whole number.

The square root of lets just say 25 means you are finding a number that multiplied by itself will equal 25 (the answer is 5).

Now for 13, there is no perfect square, however the closest whole number that multiplied by itself to 13 is 4.

4*4= 16

3*3=9

5*5=25

As you can see above 4 is the closest number to 13.

Now, the ACTUAL value of the square root of 13 is 3.60555128, but we are rounding up to the nearest whole number which is 4 :)

4 0

3 years ago

Find the greatest common factor.<br> 3a2x2 + 3a2x + 3a2

hammer [34]

Answer:

3a2

Step-by-step explanation:

You can find it in all the terms

4 0

3 years ago

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Brad invests $3700 in an account paying 3% compounded monthly. How much is in the account after 8 months?

Ymorist [56]

Answer:

Amount after 8 month (A) = $3775 (Approx)

Step-by-step explanation:

Given:

Amount invested (P) = $3,700

Rate of interest (r) = 3% = 0.03 / 12 = 0.0025 monthly

Number of month (n) = 8 month

Find:

Amount after 8 month (A)

Computation:

$A=P(1+r)^n\\\\ A=3700(1+0.0025)^8\\\\A=3700(1.02017588)\\\\ A = 3774.650676$

Amount after 8 month (A) = $3775 (Approx)

5 0

3 years ago

The proportion of high school seniors who are married is 0.02. Suppose we take a random sample of 300 high school seniors; a.) F

MrRissso [65]

Answer:

a) Mean 6, standard deviation 2.42

b) 10.40% probability that, in our sample of 300, we find that 8 of the seniors are married.

c) 14.85% probability that we find less than 4 of the seniors are married.

d) 99.77% probability that we find at least 1 of the seniors are married

Step-by-step explanation:

For each high school senior, there are only two possible outcomes. Either they are married, or they are not. The probability of a high school senior being married is independent from other high school seniors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$n = 300, p = 0.02$

a.) Find the mean and standard deviation of the sample count X who are married.

Mean

$E(X) = np = 300*0.02 = 6$

Standard deviation

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.02*0.98} = 2.42$

b.) What is the probability that, in our sample of 300, we find that 8 of the seniors are married?

This is P(X = 8).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{300,8}.(0.02)^{8}.(0.98)^{292} = 0.1040$

10.40% probability that, in our sample of 300, we find that 8 of the seniors are married.

c.) What is the probability that we find less than 4 of the seniors are married?

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{300,0}.(0.02)^{0}.(0.98)^{300} = 0.0023$

$P(X = 1) = C_{300,1}.(0.02)^{1}.(0.98)^{299} = 0.0143$

$P(X = 2) = C_{300,2}.(0.02)^{2}.(0.98)^{298} = 0.0436$

$P(X = 3) = C_{300,3}.(0.02)^{3}.(0.98)^{297} = 0.0883$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0023 + 0.0143 + 0.0436 + 0.0883 = 0.1485$

14.85% probability that we find less than 4 of the seniors are married.

d.) What is the probability that we find at least 1 of the seniors are married?

Either no seniors are married, or at least 1 one is. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

From c), we have that $P(X = 0) = 0.0023$ . So

$0.0023 + P(X \geq 1) = 1$

$P(X \geq 1) = 0.9977$

99.77% probability that we find at least 1 of the seniors are married

5 0

3 years ago

Describe how u labeled the bar model and wrote a number sentence to solve the problem

Gnom [1K]

"You draw a number line and write what you did and make up names and numbers and then do your work."

7 0

3 years ago

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