Answer:
The corrected question is:
Write an SQL statement to display the WarehouseID, the sum of QuantityOnOrder and sum of QuantityOnHand, grouped by WarehouseID and QuantityOnOrder. Name the sum of QuantityOnOrder as TotalItemsOnOrder and the sum of QuantityOnHand as TotalItemsOnHand. Use only the INVENTORY table in your SQL statement.
Answer to this corrected question:
SELECT WarehouseID,
SUM(QuantityOnOrder) AS TotalItemsOnOrder,
SUM(QuantityOnHand) AS TotalItemsOnHand
FROM INVENTORY
GROUP BY WarehouseID, QuantityOnOrder;
According to the given question:
SELECT WarehouseID,
SUM(QuantityOnOrder) + SUM(QuantityOnHand) AS TotalItemsOnHand
FROM INVENTORY
GROUP BY WarehouseID, QuantityOnOrder;
Explanation:
- In the SQL statement SELECT statement is used to select the data from the table. Here the SELECT statement is used to select WarehouseID, Sum of the columns QuantityOnOrder and QuantityOnHand from INVENTORY table.
- The sum of QuantityOnOrder and QuantityOnHand columns are given the name of TotalItemsonHand (In case of the corrected question the sum of column QuantityOnOrder is named as TotalItemsOnOrder and the column QuantityOnHand is named as TotalItemsOnHand
) using Alias AS. Alias is the temporary name given to the columns or table to make them more readable.
- GROUP BY statement is used to arrange or "group" same data and is often use with aggregate functions like SUM function here. So the grouping here is done based on two columns WarehouseID and QuantityOnOrder.
- SUM function in this SQL statement is an aggregate function to calculate the sum of all value in the columns QuantityOnOrder and QuantityOnHand.
Answer:
(a) someFunc(3) will be called 4 times.
(b) For non negative number n someFunc method calculates 2^2^n.
Explanation:
When you call someFunc(5) it will call someFunc(4) two time.
So now we have two someFunc(4) now each someFunc(4) will call someFunc(3) two times.Hence the call to someFun(3) is 4 times.
someFunc(n) calculates someFunc(n-1) two times and calculates it's product.
someFunc(n) = someFunc(n-1)^2..........(1)
someFunc(n-1)=someFunc(n-2)^2..........(2)
substituting the value form eq2 to eq 1.
someFunc(n)=someFunc(n-2)^2^2
.
.
.
.
= someFunc(n-n)^2^n.
=2^2^n
2 raised to the power 2 raised to the power n.
Answer:
divide it into smaller pieces
Explanation:
Usually, the main reason a programmer does not understand a problem fully is that there is too much information. The best way to try and fully understand a problem is to divide it into smaller pieces. Start off by answering the question what is the expected output for an input. Then divide each individual issue within the problem. This will allow you as a programmer/developer to create an individual solution for each individual issue within the problem and then test to make sure that the input gives the correct output.
IP addresses provide a unique number for identifying devices that send and receive information on the Internet
-scav
