The new volume of the hydrogen gas in the balloon is 1.5 L.
<u>Explanation:</u>
At STP, Temperature, T1 is 0° C = 0 + 273 K = 273 K
Pressure, P1 = 1 atm
Here given volume, V1 = 3.60 L
Balloon at sea,
Pressure, P2 = 2.5 atm
Temperature, T2 = 10° C = 10 + 273 = 283 K
Volume, V2 = ?
Here, we have to use the equation,
We have to rearrange the equation to get V2 as,
Now plugin the values as,
V2 = 
= 1.5 L
So the new volume of the hydrogen gas is 1.5 L.
Answer:
Can you repost this but flip it? It’s upside down rn
Explanation:
According to Avogadro's Law, same volume of any gas at standard temperature and pressure will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).
Data Given:
n = moles = ?
V = Volume = 16.8 L
Solution:
As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....
= ( 1 mole × 16.8 L) ÷ 22.4 L
= 0.75 moles
Result:
16.8 L of Nitrogen gas will contain 0.75 moles at standard temperature and pressure.
Zn + H₂SO₄ = ZnSO₄ + H₂
answer (3) <span>single replacement
hope this helps!</span>
Chlorophyll is the answer
