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pychu [463]
3 years ago
5

What is the center of the circle given by the equation (x-2)^2 + (y+4)^2 = 6

Mathematics
2 answers:
Kay [80]3 years ago
8 0
The equation of circle with center (g,f) and radius r is given by,
(x-g)² + (y-f)² = r²

Now, compare equation (x-2)² + (y+4)² = 6 with the above equation.
g = 2 and f = -4
Therefore, center of the circle is (2,-4)
ValentinkaMS [17]3 years ago
8 0

Answer: 2,-4 is the answer

Step-by-step explanation:

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tia_tia [17]

Answer:

y=11

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Step-by-step explanation:

y =-x+7

2x-5y=-7

insert the first equation into the second like so...

2x+5x-35=-7

Now rearrange...

2x+5x=-7+35

Now solve...

7x=-28

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Now incert x in any equation...

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2/n^4

Step-by-step explanation:

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3 years ago
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What values of b and c make ADEF AWVU?
Alex

Answer:

b = 10, c = 9

Step-by-step explanation:

For the triangles to be congruent by the HL postulate, then

UW = DF ( hypotenuse are congruent ), that is

12b - 34 = 5b + 36 ( subtract 5b from both sides )

7b  0 34 = 36 ( add 34 to both sides )

7b = 70 ( divide both sides by 7 )

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and

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3 years ago
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solong [7]

Answer:

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Step-by-step explanation:

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amm1812

Answer:

t = 2.58333

Step-by-step explanation:

use the distributive property:

200 = 16(6t - 3)

multiply the 16 to each value in the parenthesis:

200 = 96t - 48

now add 48 to both sides:

200 = 96t - 48

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