3 years ago

What is the center of the circle given by the equation (x-2)^2 + (y+4)^2 = 6

2 answers:

8 0

The equation of circle with center (g,f) and radius r is given by,
(x-g)² + (y-f)² = r²

Now, compare equation (x-2)² + (y+4)² = 6 with the above equation.
g = 2 and f = -4
Therefore, center of the circle is (2,-4)

ValentinkaMS [17]3 years ago

8 0

Answer: 2,-4 is the answer

Step-by-step explanation:

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