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sergiy2304 [10]
3 years ago
10

Russel throws a soda from the balcony of his house to his friend Jones in the pool. If the soda is released 20 feet from the gro

und, and is thrown with a downward velocity of 2 ft/s, how long till the soda hits the pool, ignoring air resitance? Use the formula , where h is the height of the soda in feet and t is the time in seconds since Russel threw it. Round your answer to the nearest tenth.
A. 0.5 seconds B. 0.8 seconds C. 1.1 second D. 1.6 seconds
Mathematics
2 answers:
stepladder [879]3 years ago
3 0
Using the formula S = ut +1/2at²
S=h= 20ft, u = 2ft/s, and a = 10m/s²
Thus; 20 =2t + 20t²
Therefore; 20t²+2t-20=0
Solving the equation quadratically for the value of t,
we get; t = 1.057 or t=-1.182
But t can not be negative,
 Therefore, t= 1.1 seconds (to the nearest tenth)


ki77a [65]3 years ago
3 0

Answer:

C. 1.1 seconds

Step-by-step explanation:

The formula to use is :

h=ut+\frac{1}{2}at^{2}

Where: h is the height of 20 ft, u is the velocity of 2ft/s and a is the gravitational acceleration of 9.8m/s². The acceleration should be converted to ft/sec² to simplify calculations. The value is then 32.15ft/sec².

Substituting these values into the equation:

20=2t+0.5*32.15t^{2} \\20=2t+16.075t^{2} \\0=16.075t^{2}+2t-20

Using the quadratic formula, t can be solved.

a = 16.075, b = 2, c = -20:

t=\frac{-b+-\sqrt{b^{2}-4ac} }{2a} \\t=\frac{-2+-\sqrt{2^{2}-4(16.075)(-20)} }{2(16.075)}\\t=\frac{-2+-35.92}{32.15}\\t=1.055 \\OR\\t=-1.179

The answer cannot be negative, therefore the answer is t = 1.055 ≈ 1.1seconds

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Segment CD has point E located on it such that CE:ED = 3:5. If the endpoints are located at C(5, -6) and D(11,18) then what are
wlad13 [49]

Answer:

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Step-by-step explanation:

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