It can form long chains, unlike any other element
It is found in every life-related chemical
Note: We must keep the units we use consistent. The Cp is given in cal/gC so we will use cal for energy, grams for mass and C for temperature.
1)
Heat supplied can be calculated using:
Q = mCpΔT; where m is the mass, Cp is the specific heat capacity and ΔT is the temperature change.
Q = 367 x 0.092 x (60 - 23)
Q = 125 Cal
2)
Using the same equation:
125 = 60 x 0.092 x (T - 23)
T = 45.6 C
Answer: - 0.75
Explanation:
For this question, you must remember that a fraction can be written of division.
So, -3/4 = -0.75, between -0.7 and -0.8 on the number line.
Find volume of pillow
L=78cm
B=55cm
H=25cm
Now
Mass=5.5kg
Density of water=1000kg/m^3
As it is less than density of water it will float on water
Answer:
fraction of vacancies for this metal FV = 1.918*10⁻⁴
Explanation:
Given:
The number of vacancies per unit volume => ( Nv = 1*10²⁵ m⁻³ )
But we know that Avogrado's constant NA = 6.022*10²³ atoms/mol
Density of the material is given in g/cm3 we need to convert it to g/m³
Density of material ( p ) in g/m³ :
To convert we know that
1 g/cm³ = 1000000 g/m³ then
7.40 * ( 1000000 ) = 7.40*10⁶ g/m³
So, Density of material ( p ) in g/m³ = 7.40*10⁶ g/m³
Given Atomic mass = 85.5 g/mol
To Calculate the number of atomic sites per unit volume , we will use the below formula by substituting those values above
N = NA * p / A
N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5
N = 4.45*10³⁰ / 85.5
N = 5.212*10²⁸ atoms/m³
We can now Calculate the fraction of vacancies using the formula below;
Fv = Nv / N
Fv = 1*10²⁵ / 5.212*10²⁸
fraction of vacancies for this metal at 600c.= 1.918*10⁻⁴
