Question

2. If a gas at 500 mL has a temperature of 45°C, then what is the new volume when the temperature is increased to 65°C? Show your work.

Answer 1

Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= $\frac{V1 * T2}{T1}$= $\frac{0.5 L * 338K}{318K}$ = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml