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IceJOKER [234]
3 years ago
13

A 30 ky child running at 7 m/s jumps onto a 10 kg sled which was initially at rest. What will be the

Physics
1 answer:
Ede4ka [16]3 years ago
7 0
Hope this helps. If you need clarification just ask me!

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The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. A distance of 3.5 × 10–5 m separates the plates. The p
djverab [1.8K]

Answer:

capacitance of the capacitor = 0.18 μ  F

Explanation:

Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²

distance between the plate d = 3.5 × 10–5 m

dielectric value for Teflon K = 2.1

capacitance of capacitor = ?

Formula for capacitance of parallel plate is as follows ,

C= \frac{K\epsilon_0 A}{d} (Where \epsilon_0 = 8.82 \times 10^-12\ \frac{F}{m} )

putting the values in the equation,

C = \frac{2.1\times8.82\times10^-12\times0.3402 }{3.5\times10^-5} =0.18\times 10^-6 =0.18 μ  F

4 0
3 years ago
How long does it take a wave to travel 1200 meters with the speed of 3 X 108m/sec?
Vladimir79 [104]
Around 3.70 seconds unless traveling through media

5 0
3 years ago
A child whose weight is 287 N slides down a 7.20 m playground slide that makes an angle of 31.0° with the horizontal. The coeff
natulia [17]

Answer:

a

H  =212.6 \  J

b

v  =  7.647  \  m/s

Explanation:

From the question we are told that

   The child's weight is  W_c  =  287 \ N

    The length of the sliding surface of the playground is  L =  7.20 \  m

    The coefficient of friction is  \mu =  0.120

      The angle is \theta = 31.0 ^o

      The initial  speed is  u =  0.559 \  m/s

Generally the normal force acting on the child is mathematically represented as

=>    N  =  mg  *  cos \theta

Note  m *  g  =  W_c

Generally the frictional force between the slide and the child is    

         F_f  =  \mu *  mg  *  cos \theta

Generally the resultant force acting on the child due to her weight and the frictional  force is mathematically represented as

      F =m* g sin(\theta) - F_f

Here  F is the resultant force and it is represented as  F =  ma

=>   ma =   m* g sin(31.0)  - \mu *  mg  *  cos (31.0)

=>   a =  g sin(31.0)-  \mu *  g  *  cos (31.0)

=>  a =    9.8 *  sin(31.0) - 0.120 *  9.8  *  cos (31.0)

=>a =  4.039 \ m/s^2

So

   F_f  =  0.120  * 287  *  cos (31.0)

=> F_f  = 29.52 \  N

Generally the heat energy generated by the frictional  force which equivalent tot the workdone by the frictional force  is mathematically represented as

     H  =  F_f  * L

=>  H  = 29.52 *  7.2

=>  H  =212.6 \  J

Generally from kinematic equation we have that

    v^2  =  u^2  +  2as

=>  v^2  =  0.559^2  +  2 * 4.039 * 7.2

=>  v  =  \sqrt{0.559^2  +  2 * 4.039 * 7.2}

=>  v  =  7.647  \  m/s

   

6 0
3 years ago
An car is brought to rest in a distance of 652 m using a constant acceleration of -2.7 m/s2. What was the
Goshia [24]

Answer:

I’m so sorry I tried solving it but I don’t understand it can you explain the question a little bit more ty

Explanation:

7 0
3 years ago
Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a fa
RoseWind [281]

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

8 0
2 years ago
Read 2 more answers
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