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NeTakaya
3 years ago
10

The diffusion coefficient for aluminum in silicon is DAl in Si= 4 × 10-13 cm2/s at 1300 K. What is a reasonable value for DAl in

Si at 1600 K ? Note: Rather than performing a specific calculation, you should be able to justify your answer from the options below based on the mathematical temperature dependence of the diffusion coefficient assuming a positive activation energy for diffusion.
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
4 0

Answer:

D = 4x10^-11

Explanation:

an increase in temperature would cause a resultant increase in diffusivity. as temperature rises, thermal energy of atoms would also rise and this would cause them to go faster.

4x10^-11cm²/s satisfies this condition because there is a temperature increase from 1300 to 1600.

DAI in Si = 4x10^-13cm²/sec at 1300

DAI in Si at 1600

D increases

temperature also increases

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3. Fill in: Name the organelle or organelles that perform each of the following functions.
Mekhanik [1.2K]

A. Chloroplasts

B. The cell wall and the vacuole

C. Vacuoles

D. The mitochondrion

8 0
3 years ago
The production of new skin cells to replace those that have been lost is an example of what characteristic of life?
Alchen [17]

The production of new skin cells is example of regeneration.

Regeneration is process of replacing or restoring not just skin cells, but also other cells in the human organism.

Skin regeneration is replacement of damaged tissue with new tissue.

There are two ways of skin regeneration:

1) reconstruction is a process of rebuilding of damaged skin cells

2) restoration is process of replacing broken cell skins

Epidermal stem cells are those who produces new daughter cell skins.

Epidermal stem cells are in the lowest layer of the skin.

More about skin: brainly.com/question/306377

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5 0
1 year ago
The carbon-14 content of a wooden harpoon handle found in an Inuit archaeological site was found to be 61.9% of the carbon-14 co
astraxan [27]

Answer:

3,964 years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

  • The half-life of the element is 5,730 years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(5,730 years) = 1.21 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 1.21 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 100%).

[A] is the remaining concentration of the sample ([A] = 61.9%).

∴ t = (1/k) ln([A₀]/[A]) = (1/1.21 x 10⁻⁴ year⁻¹) ln(100%/61.9%) = 3,964 years.

7 0
3 years ago
Identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent for the following equation
bazaltina [42]

The element that gains electrons, becomes reduced.

While the one which loses electrons, becomes oxidized.

In this equation,

CH₃OH + Cr₂O₇²⁻---- --> CH₂O + Cr³⁺.

By balancing the equation, we will get:

3CH₃OH + Cr₂O₇²⁻ + 8H⁺ --> 3CH₂O + 2Cr³⁺ + 7H₂O

Here the oxidation state of Cr changes from +6 to +3 that is it is being reduced thus serving as a oxidizing agent while other element retain their charges.

Here Cr₂O₇²⁻ is reduced while CH₃OH is oxidized.

So Cr₂O₇²⁻ serves as a oxidizing agent, while CH₃OH serves as reducing agent .

4 0
3 years ago
Please help!
liberstina [14]

Answer:

To help determine what type of rock it is

Explanation:

Geologists can use information such as color, hardness, grain size, texture and other aspects of the rock to figure out the classification of a rock. for example, a light blue rock with no visible grain that is translucent and has a hardness of 9 is most likely going to be a saphire. hope this helps!!!!

8 0
2 years ago
Read 2 more answers
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