We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Answer:
it's not even in the pic
Step-by-step explanation:
the q isn't even there
Answer:√5 - √2
Step-by-step explanation:
= √(5 + 2 - 2√10 )
= √{(√5)² +(√2)² - 2.√5.√2}
= √(√5 - √2)² (by identity a² + b² -2ab = ( a-b)²)
= √5 - √2
