Answer:
|GH| = 5,7 cm
Step-by-step explanation:
To know |GH|, you first need to find the length of |GD|.
We can calculate |GD| by;
cosG = |GC| / |GD|
<=> |GD| = |GC| / cosG
=> |GD| = 3,9 cm/ 0,62 = 6,33 cm
We now can easily calculate |GH| with the sinus of angle D;
sinD = |GH| / |GD|
<=> |GH| = sinD.|GD|
=> |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm
I hope i did not make a mistake ...
This has both a horizontal and a vertical asymptote. There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator. If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0. But we also have a vertical asymptote, which occurs where the denominator = 0. We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.
Answer:
1) Factor form : 
2) 8 second after launch.
Step-by-step explanation:
The height of the ball (in meters above the ground) t seconds after launch is modeled by
To find the time when ball hit the ground, we need to find the factor form of the given function.
When ball hi the ground, then height of the ball from the ground is 0.
Using zero product property, we get
Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.
Answer:
92
because the formula for the triangle is 1/2×b×h
and the formula for the rectangle nos l×w and then add those.
To know if there is a perfect square you gotta see if there is a minus sign before the second coefficient and when you square the second coefficient divided by 2 you should get the third coefficient
