Question

The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis. Determine the magnitude of the force Find the angle θ.

Answer 1

Answer: F = 776.18N θ = 29.41°

Question:

The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.

Attached is the image.

Explanation:

To solve this question we need to resolve the forces to the x and y axis.

For the x axis;

Fcosθ = 700cos15....1

For the y axis;

200 = Fsinθ - 700sin15

Fsinθ = 200 + 700sin15 ...2

Dividing equation 2 by 1

Fsinθ/Fcosθ = (200 + 700sin15)/700cos15

Tanθ = (200 + 700sin15)/700cos15

θ = Taninverse(200 + 700sin15)/700cos15)

θ = 29.41°

From equation 1;

F = 700cos15/cosθ

F = 700cos15/cos29.41

F = 776.18N