Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the h
igher track? _________
a. cars travel faster on the lower track
b. cars travel faster on the higher track
c. There is no difference in speed
How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is__________
a. Shorter
b. Longer
c. Equal
Calculate speeds for each track. How much faster was the car on the higher track than the lower track?__________
a. .56 m/s
b. 1.54 m/s
c. 3.50 m/s
a. cars travel faster on the lower track
b. cars travel faster on the higher track
c. There is no difference in speed
How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is__________
a. Shorter
b. Longer
c. Equal
Calculate speeds for each track. How much faster was the car on the higher track than the lower track?__________
a. .56 m/s
b. 1.54 m/s
c. 3.50 m/s
2 answers:
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Answer:
H_w = 2.129 m
Explanation:
given,
Width of the weir, B = 1.2 m
Depth of the upstream weir, y = 2.5 m
Discharge, Q = 0.5 m³/s
Weir coefficient, C_w = 1.84 m
Now, calculating the water head over the weir
now, level of weir on the channel
H_w = y - H
H_w = 2.5 - 0.371
H_w = 2.129 m
Height at which weir should place is equal to 2.129 m.
The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get
Therefore. the elastic potential energy stored in the spring is 6.75J .
Learn more about potential energy here:
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