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melamori03 [73]
3 years ago
15

PLEASE HELP ME!!!!!!!

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

:))

Step-by-step explanation:

Collect like terms, keeping the integer rules in mind

5. 5a + 9b - 3a + 2b + 4a

   5a + 4a - 3a + 9b + 2b (REARRANGE, if you find it to help)

   6a + 11b

6. 7m + 3n - 8m + 2n + 10m

   7m + 10m - 8m + 3n + 2n

   9m + 5n

10. 10m²n + 5mn + 9m²n - 2mn

     10m²n + 9m²n + 5mn - 2mn

     19m²n + 3mn

Try to do the rest on your own :)

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Step-by-step explanation:

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3 years ago
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Mars2501 [29]

The answer is A) 2x + 7.

When you are doing synthetic division, you always pull down the first number to the end area like this.

1 ║ 2 9 7

2

After that you multiply it's result by the number in the front. Then you add it's result to the second number. 2 * -1 = -2. So we add -2 to 9 and pull that down.

1 ║ 2 9 7

2 7

Now we repeat that process and multiply the 7 by -1. The result is -7, and we add that to 7.

1 ║ 2 9 7

2 7 0

If the end result is 0, that means the division went in evenly, with no remainders. We can now add an decreasing number of x's to all of the numbers that came through other than 0.

2x + 7

4 0
3 years ago
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ElenaW [278]

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Step-by-step explanation:)

3 0
3 years ago
Read 2 more answers
Line h contains the points (3,0) and (0,4). which point lies on a line that is perpendicular to line h and passes through point
Iteru [2.4K]
(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4

y = mx + b
slope(m) = 3/4
(-6,-5)....x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2

and ur point (6,4) lies on the perpendicular line <===


6 0
3 years ago
Can you guys help me with this math questions
dimulka [17.4K]

Answer:

2)  $40 per shirt

3)  80/9 m = 8.9 m (nearest tenth)

Step-by-step explanation:

The first question has been answered here: brainly.com/question/27846862

------------------------------------------------------------------------------------------------------

<u>Question 2</u>

Given information:

  • Previous sales = 300 shirts at $20 each
  • For every $1 increase in price, the number of sales diminishes by 5

Let x = number of $1 increases

Let y = total revenue (in dollars)

From the given information:

  • Price change of shirt:  (20 + x)
  • Number of sales change:  (300 - 5x)

Therefore, we can create a <u>quadratic equation</u> with the given information:

\implies y = (20+x)(300-5x)

As we need to find the maximum amount of revenue, we need to find the vertex of y.  As the equation is already factored, the quickest way to do this is to the find the mid-point of the zeros (since a quadratic curve is symmetrical).

\begin{aligned}y & =0\\\implies (20+x)(300-5x) & =0\\\implies (20+x) & =0 \implies x=-20\\\implies (300-5x) & = 0 \implies x=60\end{aligned}

\textsf{Midpoint}=\dfrac{-20+60}{2}=20

Therefore, Sammy should have 20 $1 increases to maximize the revenue, so the new price will be:

\implies \$20 + 20 \times \$1 = \$40\: \sf per\:shirt

------------------------------------------------------------------------------------------------------

<u>Question 3</u>

Given information:

  • Bridge is modeled as a parabola
  • Width of bridge = 30 m
  • Max height of bridge = 10 m high (in the middle)

As the bridge is modeled as a parabola, and we have been given the width and height, we can create a quadratic equation using the vertex form.

Vertex form:  y=a(x-h)^2+k

where:

  • x is the horizontal distance of the bridge
  • y is the height of the bridge
  • (h, k) is the vertex
  • a is some constant

Middle of the bridge = 30 m ÷ 2 = 15 m

Max height of the bridge = 10 m

Therefore, the vertex of the parabola is (15, 10)

\implies y=a(x-15)^2+10

We know that when x = 0, y = 0.  Therefore, substitute these values into the equation and solve for a:

\implies 0=a(0-15)^2+10

\implies 0=225a+10

\implies 225a=-10

\implies a=-\dfrac{10}{225}

\implies a=-\dfrac{2}{45}

Therefore, the equation of the parabola is:

\implies y=-\dfrac{2}{45}(x-15)^2+10 \quad \quad \textsf{for }0\leq x\leq 30

The horizontal distance at 5 m right of the middle is:

\implies \dfrac{30}{2}+5=20\:\sf m

Therefore, to find the height at this point, input x=20 into the equation and solve for y:

\implies -\dfrac{2}{45}(20-15)^2+10=\dfrac{80}{9}\:\sf m

Therefore, the height of the bridge at 5 m to the right of the middle is:

\dfrac{80}{9}\:=8.9\: \sf m\:(nearest\:tenth)

3 0
2 years ago
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