<img src="https://tex.z-dn.net/?f=%28x%20-%202%29%20%7B%20%7D%5E%7B2%7D%20%20%3D%200" id="TexFormula1" title="(x

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Serhud [2]

3 years ago

0" alt="(x - 2) { }^{2} = 0" align="absmiddle" class="latex-formula">
How many solutions does this equation have?

Mathematics

1 answer:

lesya [120]3 years ago

3 0

One solution answer is x=2

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Thirty-five more than .8 times a number is the same as 43 less than the product of -7 and the number

nydimaria [60]

Answer:

0.8x + 35 = -7x - 43

The number is -10.

Step-by-step explanation:

Let x = the number.

0.8x + 35 = -7x - 43

7.8x = -78

x = -10

4 0

3 years ago

1. (x + 4)(x-6) 2. (3x + 4)(3x - 4) 3. x^ - 9x + 18 Please help me solve

zloy xaker [14]

Answers:
1. x^2 - 2x - 24
2. 9x^2 - 16
3. (x - 3)(x - 6)

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"

qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that $\arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)$

Also, $-\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)$

This means our original expression is equal to:

$\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]$

Using the cosine addition formula, which states $\cos(a+b)=\cos a \cos b-\sin a \sin b$ , we get this itself is equal to:

$\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)$

Since $\sin^{2} \theta+\cos^{2} \theta=1$ , we know that:

$\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}$

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

$\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}$

3 0

2 years ago

WILL GIVE FIRST ANSWER THE BRAINLIEST!!!!!!!!!!!!! PICTURE BELOW

Hunter-Best [27]

For this one, plug in your x and y intercepts for the corresponding letters and see which one is true. I always start with the first equation and then see which ones solve it first, that will cut your time down on a test.

Lets start with A. (4,5)

and the first equation y=x+1

5=4+1, which is true so A is a potential answer

B. (2,3)

3=2+1, B is a potential as well

C. (-2,1)

1=-2+1, which is false so C is out

D. (-4,-3)

-3=-4+1, which is true.

To cut down on time, do the same thing with the second equation and your final answer will be A. (4,5)

4 0

3 years ago

The Roaming Cell Phone Company charges $15.00 per month plus $0.20 per minute of

Yanka [14]

It wouldn’t be any of these I don’t think, however I don’t know what the # means.

I thought it would be C = 15 + x(0.20)

Hope this helps

5 0

3 years ago