1 answer:
You might be interested in
Answer:
m=2
Step-by-step explanation:
I hope this was helpful.
Answer:
0.6892 = 68.92% of bottles are within specification.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
On average, each bottle contains 2.07 liters of soda, with a standard deviation of 0.06 liters.
This means that
The plant’s quality manager wants to determine how well the process is operating.
To do this, we find the proportion of bottles within specification.
The specification limits for a bottle of soda are 2.1 liters and 1.9 liters
This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.9. So
X = 2.1
has a pvalue of 0.6915.
X = 1.9
has a pvalue of 0.0023
0.6915 - 0.0023 = 0.6892
0.6892 = 68.92% of bottles are within specification.
The correct interpretation of the standard deviation of the given discrete distribution is:
The mean number of days a member worked out would typically be about 1.6764 from the expected number of days.
<h3>What are the mean and the standard deviation of a discrete distribution?</h3>- The mean of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.
- The standard deviation is the square root of the sum of the difference squared between each outcome and the mean, multiplied by it's respective probabilities.
Hence:
E(X) = 0.4(0) + 0.12(1) + 0.13(2) + 0.15(3) + 0.06(4) + 0.02(5) + 0.02(6) + 0.01(7) = 1.36
Hence the correct option is:
The mean number of days a member worked out would typically be about 1.6764 from the expected number of days.
More can be learned about discrete distributions at brainly.com/question/24855677
#SPJ1