A water delivery truck is filling the water tank at Morgan's house. The truck arrived with 2400 L of water. The number of liters
, L, remaining in the truck at time t minutes decreases at a rate of 110 L/min. Write an equation to represent this situation and then find how long it takes for the truck to have 1100 L left.
2 answers:
Answer:
11.81 minutes
Step-by-step explanation:
Here is a simple step-by-step explaination of how to solve this word problem:
Since the truck has 2,400L in it to begin with, the first part of our equation will be 2,400L
Next we know that the water in the truck decreases at a <u>rate</u> of 110L/min, or <u>Liters per minute</u>.
So we will put that in the equation:
Now that we have our equation set up, its time to solve.
To figure out how much water it needs to lose in <u>total</u> to end up with 1100 L left, we subtract 1,100 from 2,400.
Now we can take that number and divide it by how many liters per minute were lost.
So the total amount of time it took for the truck to have 1,100 L left is 11.81 minutes. Your answer would be
B. min
Hope this helps! : )
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Answer: Can I get brainliest and 5 stars? thank you.
a)
b)
c)
Step-by-step explanation:
a) I can't put line above it, but the line expresses that 6 and 5 and repeating infinitely. Let X equal the decimal number.
First multiply by 1 followed by as many zeros as repeating numbers there are. In this case since 6 and 5 are the repeating numbers, we have to add 2 zeros which is basically multiplying by 100
0.65*100=65.65 (another 65 remains on the right because they're infinite.)
Now substract from the original number. Now we have a new equation that says: .
Substract equation 1 from equation 2.
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Solve just like any other equation. Divide by 99 to isolate x.
This is the fraction.
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b) This one is a little bit different because we only have 1 repeating number.
In this case we have to multiply by 10.
Equation 1:
Equation 2:
Substract.
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divide by 9 to isolate x
To get rid of the decimal in the numerator, multiply both numerator and denominator by 10 so that we don't change the fraction.
and this is your fraction.
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c) 0.65 this one has no repeating number. It's a finite decimal number.
I assume you already know that; , so, we can do the same here to have a fraction.
Now, in order to get rid of the decimal, multiply by 1 followed by as many zeros as decimal numbers are. In this case 2 zeros because there are 2 decimal numbers, so it's 100. Remember that if you do it in the numerator, you have to do it in the denominator as well to not change the fraction.
Simplify if possible.
This is your fraction.
I hope this helps you feel free to contact me
