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4 years ago

Which quadrilateral will always have 4-fold reflectional symmetry?

Mathematics

2 answers:

saul85 [17]4 years ago

5 0

Answer:

trapezoid

Step-by-step explanation:

andrew11 [14]4 years ago

3 0

Answer:

trapezoid

Step-by-step explanation:

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50 POINTS BRAINLIEST

Ugo [173]

Answer:

31 degrees

Step-by-step explanation:

Measure angles 1 and 3 are vertical angles, meaning they are equal which means 3 = 149 degrees

Angles 2 and 3 are adjacent and supplementary, meaning that their angles add up to 180.

1<u>8</u>0 - 149 = 31 degrees

6 0

3 years ago

Read 2 more answers

Work out the cost. 70cm of ribbon at £2.00 per metre.

Rus_ich [418]

Answer:140
Explanation: multiply 70 times 2.00

3 0

3 years ago

Median weekly earnings for women with some college for an associate degree.

babunello [35]

Using the given linear function, the formula underestimates the median weekly earnings in 2013 by $3.

<h3>What is the linear function for the estimate?</h3>

The function that estimates the median weekly earnings n years after 1980 is given by:

W = 13n + 231.

2013 is 2013-1980 = 33 years after 2000, hence the estimate is given by:

W = 13 x 33 + 231 = 660.

Since 657 < 660, the formula underestimates the median weekly earnings in 2013 by $3.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

5 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

Write the equation of a line whose slope is -4 and that passes through the point (-2,9)

kakasveta [241]

Equation of the line:

y = -4x + 1

8 0

3 years ago