Answer:
The number of child tickets = 78 and the number of adult tickets = 124
Step-by-step explanation:
Let the number of child ticket is x and the adult ticket is y
∴ x + y =202 ⇒ (1)
∵ The cost of child ticket is $6 and adult ticket is $10
∴ 6x + 10 y = 1708 ⇒ (2)
Solve the system of equations (1) and (2)
Multiply (1) by -6 to eliminate x
∴ -6x + -6y = -1212 ⇒ (3)
Add (2) and (3)
∴ 4y = 496
∴ y = 124
Substitute the value of y in (1)
∴ x + 124 = 202 ⇒ x = 202 - 124 = 78
∴ The number of child tickets = 78 and the number of adult tickets = 124
