Answer:
74 units squared
Step-by-step explanation:
we know that the area of a square or rectangle is A = L × w
so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.
so I'll start with the middle square its length is 8 and width is 8 too.
A = 8 × 8
A = 64
now we'll move on to the other small ones to the side.
the one on the right side it's length is 2 and width is 2.
A = 2 × 2
A = 4
and then the last one on the left, Length is 3, width is 2.
A = 2 × 3
A = 6
now we'll add up all of the areas to get the total area.
Total = 64 + 4 + 6
Total = 74 units squared
Answer:x=−136
Step-by-step explanation: Step 1: Simplify both sides of the equation.
2+x=
7
8
x−15
2+x=
7
8
x+−15
x+2=
7
8
x−15
Step 2: Subtract 7/8x from both sides.
x+2−
7
8
x=
7
8
x−15−
7
8
x
1
8
x+2=−15
Step 3: Subtract 2 from both sides.
1
8
x+2−2=−15−2
1
8
x=−17
Step 4: Multiply both sides by 8.
8*(
1
8
x)=(8)*(−17)
Answer:
16.8
Step-by-step explanation:
14/20 = 0.7
24 x 0.7 = 16.8
(Feel free to round up or down, or keep it the same depending on the criteria of the question!)
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
