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strojnjashka [21]
3 years ago
9

In the aftermath of a car accident, it is concluded that one driver slowed to a halt in 20 seconds while skidding 1775 feet. If

the speed limit was 60 miles per hour, can it be proved that the driver had been speeding? (Hint: 60 miles per hour is equal to 88 feet per second.) We can guarantee that at some time from when the driver first pressed on the brake to when the car came to a complete stop the car was traveling
Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0
Assume uniformly accelerated motion

Vf = Vo - at => a= [Vo - Vf] / t

Vf = 0, t = 20 s => a = Vo / 20

x = Vot - at^2 / 2

x = Vot - (Vo / 20) * t^2 /2

x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile

t = 20 s

=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo

=> Vo = 0.336 /10 = 0.0336 mile /s

Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h

Therefore, the car was way over the speed limit.



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Answer:

Probability that their hair was done by Amy is 0.475.

Step-by-step explanation:

We are given that Sally's Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done by Amy.

Let the Probability of hair cutting done by Chris = P(C) = 0.36

Probability of hair cutting done by Karine = P(K) = 0.26

Probability of hair cutting done by Amy = P(A) = 0.368

Also, let NS = event that customer is not satisfied with his cutting

So, Probability that customers are not satisfied given that their hair cutting is done by Chris = P(NS/C) = 0.05

Probability that customers are not satisfied given that their hair cutting is done by Karine = P(NS/K) = 0.06

Probability that customers are not satisfied given that their hair cutting is done by Amy = P(NS/A) = 0.08

Now, a customer leaving the salon is selected at random. If the customer is not satisfied, the probability that their hair was done by Amy is given by = P(A/NS)

For finding the above probability we will use the concept of Bayes' Theorem;

SO, P(A/NS)  =  \frac{\text{P(A) \times P(NS/A)}}{\text{P(C) \times P(NS/C) + P(K) \times P(NS/K) +P(A) \times P(NS/A) }}\frac{P(A) \times P(NS/A) }{P(C) \times P(NS/C) +P(K) \times P(NS/K) +P(A) \times P(NS/A) }

                     =  \frac{0.38 \times 0.08}{0.36 \times 0.05+0.26 \times 0.06+0.38 \times 0.08}

                     =  \frac{0.0304}{0.064}

                     =  <u>0.475</u>

<em>Hence, the probability that their hair was done by Amy is 0.475.</em>

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