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strojnjashka [21]
3 years ago
9

In the aftermath of a car accident, it is concluded that one driver slowed to a halt in 20 seconds while skidding 1775 feet. If

the speed limit was 60 miles per hour, can it be proved that the driver had been speeding? (Hint: 60 miles per hour is equal to 88 feet per second.) We can guarantee that at some time from when the driver first pressed on the brake to when the car came to a complete stop the car was traveling
Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0
Assume uniformly accelerated motion

Vf = Vo - at => a= [Vo - Vf] / t

Vf = 0, t = 20 s => a = Vo / 20

x = Vot - at^2 / 2

x = Vot - (Vo / 20) * t^2 /2

x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile

t = 20 s

=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo

=> Vo = 0.336 /10 = 0.0336 mile /s

Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h

Therefore, the car was way over the speed limit.



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PLEASE HELP
max2010maxim [7]

Hello!


So, this is quite the complex question, and here are the following steps:


What is the quotient of \frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}?

\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (rationalize the denominator)

\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

5 0
4 years ago
Bottom#4<br> Which value represents the median from the box and whisker plot attached?
Andreyy89

Answer:

Step-by-step explanation:

the median is the line inside the box which is 84

8 0
4 years ago
Plz help 100 points!!!
Bad White [126]

(5) Angle ADC is the sum of angles ADB and BDC.

(6) Yes, because lines AG and EC form two pairs of vertical angles, including ADC and EDG, as well as ADE and CDG.

(7) Angle HJK is clearly a right angle, and a right angle has measure 90°.

7 0
3 years ago
Please help!! 10 extra points
Igoryamba
HEY THERE !!

As we know that cotx= 1/tanx

cot36° = 1/tan36°

=>cot36°= 1/0.726543

=>so cot 36°= 1.376382

So correct answer is option D.


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7 0
3 years ago
2) What are the possible zeros of the following equation?<br> y = 3x4 + 4x² – 5x + 10
Nana76 [90]

Answer:

Solution:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

Answer: 3x(3x + 2)

4 0
3 years ago
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