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nexus9112 [7]
3 years ago
11

The perimeter of a rectangle is twice the

Mathematics
1 answer:
masya89 [10]3 years ago
5 0

Answer:

The length is 14 m.

Step-by-step explanation:

length = L

width = W

perimeter = P

"The perimeter of a rectangle is twice the  sum of its length and its width."

P = 2(L + W)

"The  perimeter is 40 meters"

40 = 2(L + W)

"and its length is 2  meters more than twice its width."

L = 2W + 2

Replace L with 2W + 2 in equation 40 = 2(L + W):

40 = 2(2W + 2 + W)

40 = 2(3W + 2)

20 = 3W + 2

3W = 18

W = 6

The width is 6 meters.

L = 2W + 2 = 2(6 m) + 2 m = 12 m + 2 m = 14 m

Answer: The length is 14 m.

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The value of x<em> </em>in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is <em>x </em>= 24

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The given equation is presented as follows;

\frac{3}{(x - 4) \cdot (x - 7) }  + \frac{6}{(x - 7) \cdot (x - 13)   }  + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28)  } =  -  \frac{1}{20}

Factoring the common denominator, we have;

\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28)  + 15 \cdot(x - 4) \cdot(x - 7)  - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)}   + =  -  \frac{1}{20}

Simplifying the numerator of the right hand side using a graphing calculator, we get;

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Given that the terms of the numerator have several factors in common, we get;

-(x³ - 48•x + 651•x - 2548) = -(x-7)•(x-28)•(x-13)

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