Answer:
Ok! When given points, to find the slope, you would use this equation: y2-y1/x2-x1. Let me demonstrate. In this set to find the slope with the coordinates (10,8) and (14,20), the y2 value is 20, and the y1 value is 8, and the x2 value is 14, and the y1 value is 10. So, your equation would look like this: (20-8)/(14-10), which simplifies to 12/4, or 3! So the slope is three, and that's how you do that when using an equation. OR, you could graph them, but that isn't too reliable so I do not recommend trying it, since you may not create the right slope.
Answer:
Tally table
Step-by-step explanation:
Frequency table- a table that uses numbers to record data. 3. Tally table- a table that uses tally marks to record data bran-list please i answered first i will follow you and answer more of your questions almost expert please
Answer:The ansewers are c and d.
Step-by-step explanation:
The function f(x)=x is really y=x.
Answer:
This can be solved by using the empirical rule for a normal distribution.
Step-by-step explanation:
A. The number of skateboards given is one standard deviation above the mean. Approximately 68% of the data points lie within the range plus and minus one standard deviation of the mean. Therefore the required percentage is:
68 + 16 = 84%.
B. The given number of skateboards is two standard deviations above the mean. Approximately 95% of the data points lie within the range plus and minus two standard deviations of the mean. Therefore the required percentage is:
5/2 = 2.5%
C.The given number of skateboards is one standard deviations below the mean. Therefore the required percentage is:
16%.
Hi there!
In order to solve, we'll need to use a proportion: 20/a = 21/20. Then, we'll cross-multiply and solve to find a: 21a = 400 | a = 19.05. Next, to find b, we can just use pythagorean theorem: 20^2 + (400/21)^2 = b^2 | b = 27.62.
We are using geometric mean to solve for a, then using pythagorean theorem to solve for b. If you need more help with geometric mean, or would like a complete explanation, please let me know! I'd be happy to provide you with that information.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
