This applet illustrates 95% confidence intervals for samples from a normal distribution with known variance. (a) When taking 100
1 answer:
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Given:
f(x) = sin(x)
g(x) = cos(x).
Note that because sin²x + cos²x = 1, the value for f²+g² should be equal to 1.
Create the table shown below.
x f² g² f² + g²
-------- ---------- ----------- ------------
-π 0 1 1
-0.8π 0.3455 0.6545 1
-0.6π 0.9045 0.0955 1
-0.4π 0.9045 0.0955 1
-0.2π 0.3455 0.6545 1
0 0 1 1
0.2π 0.3455 0.6545 1
0.4π 0.9045 0.0955 1
0.6π 0.9045 0.0955 1
0.8π 0.3455 0.6545 1
π 0 1 1
A sketch is shown in the figure below.
f(x) = sin(x)
g(x) = cos(x).
Note that because sin²x + cos²x = 1, the value for f²+g² should be equal to 1.
Create the table shown below.
x f² g² f² + g²
-------- ---------- ----------- ------------
-π 0 1 1
-0.8π 0.3455 0.6545 1
-0.6π 0.9045 0.0955 1
-0.4π 0.9045 0.0955 1
-0.2π 0.3455 0.6545 1
0 0 1 1
0.2π 0.3455 0.6545 1
0.4π 0.9045 0.0955 1
0.6π 0.9045 0.0955 1
0.8π 0.3455 0.6545 1
π 0 1 1
A sketch is shown in the figure below.
Hello from MrBillDoesMath!
Answer:
4/sin(80)
which is approximately 4.06
Discussion:
From the triangle, not drawn too accurately (see attachment)
sin(80) = side opposite /hypotenuse =>
sin (80) = 4/c => multiply both sides by "c"
c sin(80) = 4/c * c =>
c sin(80) = 4 => divide both sides by sin(80)
c = 4/sin(80)
and 4/sin(80) is approximately 4.06
Thank you,
MrB
