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3 years ago

How many qt equal to 5 gal

Mathematics

1 answer:

Naily [24]3 years ago

7 0

20 quarts equal 5 gallons. There are 4 quarts in a gallon so:

4 x 5 = 20

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If $5000 is invested at 7.8% interest compounded monthly, how much would you have after 54 months?

Nuetrik [128]

5000 x (1+0.078/12)^54

5000 x (1.0065)^54

$7094.37

6 0

4 years ago

Multiples of 4 are even numbers

Vesna [10]

Answer:

The statement is true

Step-by-step explanation:

Multiples of 4 (until 40): 4 , 8 , 12 , 16 , 20 , 24 , 28 , 32 , 36 , 40

All of these are even numbers

4 0

3 years ago

Read 2 more answers

How does quantitative information differ from qualitative information.

Kobotan [32]

Quantitative data refers to any information that can be quantified, counted or measured, and given a numerical value. Qualitative data is descriptive in nature, expressed in terms of language rather than numerical values.

5 0

2 years ago

The Wallow Fire of 2011 burned 538,000 acres in eastern Arizona. a. If one square mile is 640 acres, how many square miles did t

balu736 [363]

a) The fire burnt 840.6 square miles

b) The fire burnt 16.8 tempe

Step-by-step explanation:

1 square mile = 640 acres

a) to find how many square miles did the fire burn:

Total area the fire burn = 538000 acres

1 square miles = 640 acres

Concert the acres into square miles

538000/ 640 = 840.6 square miles

The fire burnt 840.6 square miles

b) 50 square miles= 1 temperatures

The no. Of tempe the fire burn = 840.6/50

= 16.8 tempe

The fire burnt 16.8 tempe

4 0

3 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

4 years ago