The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
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Answer:
The solution is the point where the lines intersect.
The answer is (-3 , -8)
Answer: Algebraically, linear functions are polynomial functions with a highest exponent of one, exponential functions have a variable in the exponent, and quadratic functions are polynomial functions with a highest exponent of two.
Step-by-step explanation: A linear equation is a type of equation in which the graph is straight and each term is a constant or a power of a constant. The formula is y=mx+b. Quadratic equations are similar to exponential equations by having a curve in the graph.