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marissa [1.9K]
3 years ago
7

A geometry student named Cornell claims that the two triangles in the diagram below are similar to one another. He asserts that

the LMN is similar to STU because the sides on the bigger triangle are spaced the same as the sides of the smaller triangle.
Explain why Cornell is mistaken in his conclusions about LMN and STU. In writing your response, be sure to explain the concept of proportionality. Also be sure to include important math vocabulary such as
similarity, corresponding sides, and ratios.

Mathematics
1 answer:
sveta [45]3 years ago
3 0
They’re similar bc all sides have the same scale factor
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Express the following as:<br>ax+by+c=0<br><br>-2x+3y=6​
Cerrena [4.2K]

The expression -22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

<h3>Linear Equations</h3>

The given equation is:

-2x + 3y = 6

Comparing the equation above with ax + by + c = 0

Rewrite -2x + 3y = 6 in the form ax + by + c = 0

-2x + 3y - 6 = 0

If -2x + 3y - 6 = 0 is compared with ax + by + c = 0

a = -2, b = 3, c = -6

Therefore, the expression-22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

Learn more on linear equations here: brainly.com/question/14323743

8 0
2 years ago
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If square root of x has a decimal approximation of 3.4, then x is between which two integers? In your final answer, include all
Zina [86]

Answer:

You know that √x = 3.4, therefore x = 3.4² = 11.56

Hope I helped :)

6 0
3 years ago
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Find the value of p in the figure below.
nirvana33 [79]

From the chord theorem we have:

4\cdot4.5=6\cdot(2p-3)\\\\18=12p-18\\\\12p=18+18\\\\12p=36\qquad|:12\\\\\boxed{p=3}

6 0
3 years ago
PLEASE ANSWER!!
ohaa [14]

Answer: 5 games

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3 0
2 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
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