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Sever21 [200]
3 years ago
6

PLEASE HELP I'M TAKING A QUIZ AND I HAVE 5 MINUTES LEFT

Mathematics
2 answers:
Kazeer [188]3 years ago
4 0

<u><em>#1 is 6.34 </em></u>

<u><em>#2 is 27.25 </em></u>

<u><em>#3 is Gallons of gas use for work and errands is 10. </em></u>

<u><em>#4 is 215 </em></u>

<u><em>Hope this helps</em></u>

vladimir1956 [14]3 years ago
4 0

Answer:

1. 0.60

2. 37.29

3. 4

4.215 miles

Mark me as brainliest

Step-by-step explanation:

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iren [92.7K]

Answer: 6,000.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help with this question!!!
marin [14]

Answer:

length: 12 ft

area: 72 square feet

Step-by-step explanation:

Let L represent the length of the mat in feet. Then L/2 is the width and the perimeter is ...

P = 36 = 2(L +L/2) = 3L . . . . . substitute the given information and simplify

12 = L . . . . . . divide by 3

The length of the mat is 12 ft.

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The width of the mat is L/2 = 6 ft, and the area is the product of length and width.

Area = (12 ft)(6 ft) = 72 ft^2

The area of the mat is 72 square feet.

7 0
3 years ago
Help? Because my teacher doesn't want too
snow_lady [41]
M<ABC = m<EBD = 36 (vertical angles)

78 - x + 36 + 3x - 10 = 180 (straight angle)

Now solve for x

78 - x + 36 + 3x - 10 = 180
2x + 68 = 180
     -  68     -68 (subtract 68 on both sides)
2x        =  58
  x        =  29
7 0
3 years ago
S(t)=9t-4, find S(4)
melamori03 [73]
For this problem, you need to substitute 4 in for your variable t. the original equation is S(t) and the one you need is S(4) -- in other words, evaluate this equation when t = 4.

S(4) = 9(4) - 4
S(4) = 36 - 4
S(4) = 32 is your answer.
3 0
3 years ago
Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan
Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation

1) For x = 3

z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5

For x = 6

z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67

For x = 70

z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19

For x = 12

z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5)  x = 90

z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6)  For x = 10

z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25

For x = 20

z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7)  For x = 7

z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67

For x = 9

z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471

8)  For x = 40

z=\frac{x-\mu}{\sigma}=\frac{40-50}{15}=-0.67

For x = 47

z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9)  x = 120

z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0
3 years ago
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