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tatiyna
3 years ago
8

The selling price of a dinner table is $250, the markup is 40%. What is the cost of the table

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0
250×.40 = 100.00

250.00+100.00 =350.00

your answer is $350.00
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The product of two consecutive even integers is 224. what are the 4 integers?
alexgriva [62]

Answer:

-16 and -14

14 and 16

Step-by-step explanation:

Let's say x is the smaller integer and x+2 is the larger integer.  Their product is 224.

x (x + 2) = 224

x² + 2x = 224

Complete the square and solve for x.

x² + 2x + 1 = 225

(x + 1)² = 225

x + 1 = ±15

x = -16 or 14

x + 2 = -14 or 16

So the integers are either -16 and -14, or 14 and 16.

8 0
3 years ago
Read 2 more answers
A school sold tickets to a musical. The school received $6.50 per ticket sold.
Kamila [148]

Answer: m=$6.50t AND t$6.50=m

Step-by-step explanation:

3 0
3 years ago
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An individual needs a daily supplement of at least 464 units of vitamin C and 252 of vitamin E and agrees to obtain this supplem
hichkok12 [17]

Answer:

z (min)  = 705

x₁  = 10

x₂  = 9

Step-by-step explanation:

Let´s call  x₁  quantity of food I ( in ou )  and x₂ quantity of food II ( in ou)

          units of vit. C   units of vit.E   Cholesterol by ou

x₁                 32                      9                         48

x₂                16                      18                          25

Objective function z

z  =   48*x₁   +  25*x₂        To minimize

Subject to:

1.-Total units of vit. C at least  464

32*x₁   +  16*x₂     ≥   464

2.- Total units of vit. E at least  252

9*x₁  + 18*x₂   ≥  252

3.- Quantity of ou per day

x₁   +   x₂   ≤  35

General constraints    x₁  ≥ 0    x₂   ≥ 0

Using the on-line simplex method solver (AtoZmaths) and after three iterations the solution is:

z (min)  = 705

x₁  = 10

x₂  = 9

5 0
3 years ago
The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan
kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points (x_1, y_1) and (x_2,y_2) is,

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Length of PQ = \sqrt{(1-1)^2+(2-6)^2}

PQ = 4

Length of PR = \sqrt{(1+4)^2+(2-2)^2}

PR = 5

Length of QR = \sqrt{(1+4)^2+(6-2)^2}

QR = \sqrt{25+16}

     = \sqrt{41}

     = 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

                                                                       = 4 + 6.4 + 5

                                                                       = 15.4 yards

4 0
3 years ago
A shipment of 50,000 transistors arrives at a manufacturing plant. The quality control engineer at the plant obtains a random sa
Aleks04 [339]

Step-by-step explanation:

remember, the number of possible combinations to pick m out of n elements is C(n, m) = n!/(m! × (n-m)!)

50,000 transistors.

4% are defective, that means 4/100 = 1/25 of the whole.

so, the probability for one picked transistor to be defective is 1/25.

and the probability for it to work properly is then 1-1/25 = 24/25.

now, 500 picks are done.

to accept the shipment, 9 or less of these 500 picks must be defective.

the probability is then the sum of the probabilities to get

0 defective = (24/25)⁵⁰⁰

1 defective = (24/25)⁴⁹⁹×1/25 × C(500, 1)

= 24⁴⁹⁹/25⁵⁰⁰ × 500

2 defective = (24/25)⁴⁹⁸×1/25² × C(500, 2)

= 24⁴⁹⁸/25⁵⁰⁰ × 250×499

3 defective = 24⁴⁹⁷/25⁵⁰⁰ × C(500, 3) =

= 24⁴⁹⁷/25⁵⁰⁰ × 250×499×166

...

9 defective = 24⁴⁹¹/25⁵⁰⁰ × C(500, 9) =

= 24⁴⁹¹/25⁵⁰⁰ × 500×499×498×497×496×495×494×493×492×491 /

9×8×7×6×5×4×3×2 =

= 24⁴⁹¹/25⁵⁰⁰ × 50×499×166×71×31×55×494×493×41×491

best to use Excel or another form of spreadsheet to calculate all this and add it all up :

the probability that the engineer will accept the shipment is

0.004376634...

which makes sense, when you think about it, because 10 defect units in the 500 is only 2%. and since the whole shipment contains 4% defect units, it is highly unlikely that the random sample of 500 will pick so overwhelmingly the good pieces.

is the acceptance policy good ?

that completely depends on the circumstances.

what was the requirement about max. faulty rate in the first place ? if it was 2%, then the engineer's approach is basically sound.

it then further depends what are the costs resulting from a faulty unit ? that depends again on when the defect is usually found (still in manufacturing, or already out there at the customer site, or somewhere in between) and how critical the product containing such transistors is. e.g. recalls for products are extremely costly, while simply sorting the bad transistors out during the manufacturing process can be rather cheap. if there is a reliable and quick process to do so.

so, depending on repair, outage and even penalty costs it might be even advisable to have a harder limit during the sample test.

in other words - it depends on experience and the found distribution/probability curve, standard deviation, costs involved and other factors to define the best criteria for the sample test.

3 0
2 years ago
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