Find two numbers whose sum is 9 and whose difference is -1

Mathematics

2 answers:

faltersainse [42]3 years ago

7 0

4 and 5 because four plus five is nine and five minus four is one

faltersainse [42]3 years ago

4 0

Answer:

4 and 5

Step-by-step explanation:

Make a system of equations:

x+y=9

x-y=-1

x=9-y

9-y-y=-1

9-2y=-1

-2y=-10

y=5

Since y=5, x must be 4 since 4+5=9 and 4-5=-1

Hope this helped!

You might be interested in

Will give brainliest if its correct and more than one person answers

myrzilka [38]

D) a = 24, c = 48, e = 22, i = 80 is the correct answer.

hope this helps!

6 0

3 years ago

Read 2 more answers

Enter the explicit rule for the sequence

Softa [21]

Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.