The coordinates of the endpoints of `bar(AB)` and `bar(CD)` are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which condition
proves that ` bar(AB)||bar(CD)`?
A.
`((y_4-y_2)/(x_4-x_2)= (y_3-y_1)/(x_3-x_1))`
B.
`((y_4-y_3)/(y_2-x_1)= (x_4-x_3)/(x_2-x_1))`
C.
`((y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1))`
D.
`((y_2-y_1)/(x_4-x_3)= (x_2-x_1)/(y_4-y_3))`
A.
`((y_4-y_2)/(x_4-x_2)= (y_3-y_1)/(x_3-x_1))`
B.
`((y_4-y_3)/(y_2-x_1)= (x_4-x_3)/(x_2-x_1))`
C.
`((y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1))`
D.
`((y_2-y_1)/(x_4-x_3)= (x_2-x_1)/(y_4-y_3))`
2 answers:
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Answer:
A. A = B
Step-by-step explanation:
Given
Required
Which of the options is true
We start by simplifying
Permutation is calculated as follows
So.
0! = 1; So
Hence. B! = P!
<em>This implies that </em><em />