The coordinates of the endpoints of `bar(AB)` and `bar(CD)` are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which condition
proves that ` bar(AB)||bar(CD)`?
A.
`((y_4-y_2)/(x_4-x_2)= (y_3-y_1)/(x_3-x_1))`
B.
`((y_4-y_3)/(y_2-x_1)= (x_4-x_3)/(x_2-x_1))`
C.
`((y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1))`
D.
`((y_2-y_1)/(x_4-x_3)= (x_2-x_1)/(y_4-y_3))`
A.
`((y_4-y_2)/(x_4-x_2)= (y_3-y_1)/(x_3-x_1))`
B.
`((y_4-y_3)/(y_2-x_1)= (x_4-x_3)/(x_2-x_1))`
C.
`((y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1))`
D.
`((y_2-y_1)/(x_4-x_3)= (x_2-x_1)/(y_4-y_3))`
2 answers:
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Answer:
2.25 seconds
Step-by-step explanation
Because you know what distance equals you can plug it into the equation
From there you can solve by dividing the 16 over and then square rooting.
You take the square-root to get rid of
