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2 years ago

In an uncomformity between two layers of rock, how is the lower layer usally described

Physics

1 answer:

xenn [34]2 years ago

6 0

The lower layer is thought to be hard and rough

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Describe the structure of an atom.

Maurinko [17]

A as an atom contains a nucleus where protons and neutrons are present. Electrons orbit the nucleus in paths called orbital

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3 years ago

The distance and direction between starting and ending positions

rodikova [14]

Answer:

The length traveled by an object moving in any direction or even changing direction is called distance. The location of an object in a frame of reference is called position. For straight line motion, positions can be shown using a number line. The separation between original and final position is called displacement

Explanation:

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3 years ago

HELP ME ASAP PLEASE

padilas [110]

Answer:

( 1000 × 4 = 4,000) (800×3= 2400) (800×2=1600) the answer is 1600 hope it helps

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3 years ago

An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by ΔV

ra1l [238]

Answer:

t = 5.48 × 10⁻³ s

Explanation:

Given:

ΔV = ΔVmax × sin(2πft)

frequency, f = 16.9Hz

thus,

ΔV = ΔVmax × sin(2π×16.9×ft)

Now,

Let 'R' be the resistance

Also according to the ohms law

i = V/R

where,

i = current

V = voltage

hence,

$i=\frac{\Delta V_{max}sin(2\pi \times 16.9\times t)}{R}$

also, given at time 't' the current in the circuit is 55.0% of the peak current

thus

$i=\frac{55}{100}\times \frac{\Delta V_{max}}{R}=0.55\times \frac{\Delta V_{max}}{R}$

thus,

$0.55\times \frac{\Delta V_{max}}{R}=\frac{\Delta V_{max}sin(2\pi \times 16.9\times t)}{R}$

$0.55=sin(2\pi \times 16.9\times t)}$

$0.5823=(2\pi \times 16.9\times t)}$

t = 5.48 × 10⁻³ s (Answer)

8 0

2 years ago

John is carrying a shovelful of snow. The center of mass of the 3.00 kg of snow he is holding is 15.0 cm from the end of the sho

Andru [333]

Answer:

James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down

Explanation:

Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards

so here we can say

Upwards force = downwards Force + weight of snow

while if we find the other force which is acting downwards

then for that force we can say that net torque must be balanced

so here we have

$F_{down} L_1 = W_{snow} L_2$

so here we have

$F_{down} = \frac{L_2}{L_1} (W_{snow})$

so here we can say that upward force by which we push up is always more than the downwards force

8 0

3 years ago