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guapka [62]
3 years ago
9

What is the significance of the Taylor experiment?

Physics
2 answers:
12345 [234]3 years ago
7 0

Answer:

B. it showed that the wave nature of light is a probability statement of where photons are going to be

Explanation:

Lera25 [3.4K]3 years ago
5 0

Answer:

B. it showed that the wave nature of light is a probability statement of where photons are going to be

Explanation:

When the light propagates through a medium it is taken to act as a wave, it shows all the features of a wave such as reflection, refraction, diffraction.

  • But when the light ray is incident on a surface generating an energy interaction with the particles of the matter on which it is incident then it is treated as matter. Light is made of particles called photons.
  • The collision of photons with the surface electrons in some materials leads to the ejection of the valance electrons from the surface in excited state.

Energy of photon is given as:

E=h.\nu

where:

h = Planck's constant

\nu= frequency of the wave

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Which one of the following is radical?<br>a.NH4+<br>b.CUSO4<br>c.CH4<br>d.NH3​
klio [65]

Answer:

The unit that is a radical among the options is;

a. NH₄⁺

Explanation:

A radical is an atom, group of atoms molecule or ion that contains an electron that is unpaired. The presence of the unpaired electrons make radical very reactive as such most radicals enter into reactions with other species or with themselves to form new compounds making them not last long.

Radicals are also known as free radicals. Examples of radicals includes; Ammonium ion, NH₄⁺

Nitrate ion NO₃⁻ (From a salt)

Hydroxide ion OH⁻ (From a base)

Sulphate ion SO₄²⁺ (From an acid)

All of which are formed in aqueous solution of acids, salts and bases.

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3 years ago
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dimaraw [331]
The radiations detected by Arno Penzias and Robert Wilson
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Today, we call those waves the "Cosmic Microwave Background".

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7 0
3 years ago
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If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.
grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution.  By definition is defined as:

\theta = 1.22\frac{\lambda}{d}

Where,

\lambda= Wavelength

d = Width of the slit

\theta= Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

r = l\theta

Relacing \theta

r = l(\frac{1.22\lambda}{d})

r = 1.22\frac{l\lambda}{d}

Replacing with our values we have that,

r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})

r = 3680.91m

Therefore the diameter of the beam on the moon is

d = 2r

d = 2 * (3690.91)

d = 7361.8285m

Hence, the diameter of the beam when it reaches the moon is 7361.82m

8 0
3 years ago
At the center of the sun, fusion converts hydrogen into
dimaraw [331]
<span>At the center of the sun, fusion converts hydrogen into helium, neutrinos and another thing that I forgot =/</span>
3 0
3 years ago
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
3 years ago
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