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sergey [27]
3 years ago
11

What are the solutions to the quadratic equation 4x^2 = 64?

Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Given

4x² = 64 ( divide both sides by 4 )

x² = 16 ( take the square root of both sides )

x = ± \sqrt{16} = ± 4

Solutions are x = - 4 and x = 4 → C

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Prices are going up in the ratio 6:5 Write a 60% decrease as a ratio.
ivolga24 [154]

Answer:

To Decrease an amount in a given Ratio, we need to multiply by a fraction that is less than one. For example, in scaling down a recipe for four people into a recipe for 3 people, we would use the ratio of 3 : 4 which means we would multiply all our recipe amounts.

3 0
2 years ago
The volume v, measured in mm3, of an object can be calculated by v=4πr353, where r is the radius of the object. if the radius is
satela [25.4K]

Since the volume of an object = \frac{4}{3}\times \Pi r^{3}

Volume= \frac{4}{3}\times (3.14) (243)^{3}

Volume= 60074091 mm^{3}

8 0
3 years ago
Factorise fully 21x² +25x =4​
Vitek1552 [10]
X= 1/7, -4/3
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6 0
2 years ago
If a,b,c are all non-zero numbers and a+b+c=0, prove that
Butoxors [25]

<em>Given - a+b+c = 0</em>

<em>To prove that- </em>

<em>a²/bc + b²/ac + c²/ab = 3</em>

<em>Now we know that</em>

<em>when x+y+z = 0,</em>

<em>then x³+y³+z³ = 3xyz</em>

<em>that means</em>

<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>

<em>Lets solve for LHS</em>

<em>LHS = a²/bc + b²/ac + c²/ab</em>

<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>

<em>by multiplying missing denominators,</em>

<em>now take common abc from denominator and you'll get,</em>

<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>

<em>Comparing one and two we can say that</em>

<em>(a³+b³+c³)/abc = 3</em>

<em>Hence proved,</em>

<em>a²/bc + b²/ac + c²/ab = 3</em>

6 0
2 years ago
Which expressions are equivalent when m = 1 and m = 4? 5 m minus 3 and 2 m 5 m 3 m 4 and m 4 2 m 2 m 7 and 3 m minus 3 m 5 m 3 a
emmasim [6.3K]

The expressions that are equivalent when m = 1 and m = 4 is;

Option B: 3m + 4 and m + 4 + 2m

We are given m = 1 and m =4;

A) 5m - 3 and 2m + 5 + m

B) 3m + 4 and m + 4 + 2m

C) 2m + 7 and 3m - 3 + m

D) 5m + 3 and 4m + 2 + 2m

For option B; 3m + 4 and m + 4 + 2m

Let's put m = 1

3(1) + 4 = 7

Also, 1 + 4 + 2(1) = 7

Similarly, let us put 4 for m to get;

3(4) + 4 = 16

Also, 4 + 4 + 2(4) = 16

In both cases, the expressions are equivalent and as such option B is the right one.

Read more about algebra simplifications at; brainly.com/question/4344214

4 0
2 years ago
Read 2 more answers
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