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3 years ago

A 10.0 m wire is hung from a high ceiling and held tightly below

Physics

1 answer:

yan [13]3 years ago

8 0

Answer:

5 m

Explanation:

Speed of waves is as the product of frequency and wavelength hence expressed as s=fw where f is the frequency of waves in Hz, s is the speed in m/s and w is wavelength in meters.

Making w the subject of the formula then

$w=\frac {s}{f}$

Substituting 335 m/s for s and 67 Hz for f then the wavelength is

$w=\frac {335}{67}=5m$

Wavelength is the distance between successive crests. Since the string is 10m, wavelengths of 5m each will be 2 and the crests will be 3.

Wavelenth=5 m

You might be interested in

Which of the following is NOT an illuminated object?

Korolek [52]

Answer:

The answer here would be light bulb.

Explanation:

An Illuminated object is simply something that reflects light. And everything in the list is illuminated except the light bulb. Humans reflect light in the same way as desks and sidewalks. If we didn't we wouldn't technically be able to see other humans unless they were luminous. This brings me to the nest point. A light bulb is a luminous object because it creates light on its own.

A good example would be this:

The Sun is a luminous object

The Moon is a illuminated object

I hope this helped and didn't confuse you more, I kind of went all over the place with the explanation. Either way, if you need more help feel free to let me know! :)

-Matt

5 0

3 years ago

Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r

Zepler [3.9K]

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms b) 0.86 amps c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

Assuming that the Resistors are in series 

a) Determine Total resistance

Req = R1 + R2 + R3

= 3 + 4 + 5 = 14 ohms

b) Total current

Ieq = V / Req

= 12 / 14 = 0.86 amps

c) The Total Voltage over the entire system

Vt = ∑ Voltage drops

= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

= 10.32 V

5 0

3 years ago

Which is a transverse wave that requires a medium to move?

Ronch [10]

the transverse wve that requires a medium to move is : sound waves in order to travel, sound waves need to jumped on between one particle to another, no matter it's liquid, solid , and gases. Which explains why you wont hear a thing in outer space, simply because the sound waves got no particle to jumped into

4 0

4 years ago

If a beam of red light and a beam of violet light are incident at the same angle on the inclined surface of a prism from air med

Kaylis [27]

Answer: The red light bends the least while the violet the most.

Explanation:

i think this is it

3 0

3 years ago

A 3.00-kg block starts from rest at the top of a 33.0° incline and slides 2.00 m down the incline in 1.80 s. (a) Find the accele

ElenaW [278]

(a) $1.23 m/s^2$

Let's analyze the motion along the direction of the incline. We have:

- distance covered: d = 2.00 m

- time taken: t = 1.80 s

- initial velocity: u = 0

- acceleration: a

We can use the following SUVAT equation:

$d = ut + \frac{1}{2}at^2$

Since u=0 (the block starts from rest), it becomes

$d=\frac{1}{2}at^2$

So by solving the equation for a, we find the acceleration:

$a=\frac{2d}{t^2}=\frac{2(2.00 m)}{(1.80 s)^2}=1.23 m/s^2$

(b) 0.50

There are two forces acting on the block along the direction of the incline:

- The component of the weight parallel to the surface of the incline:

$W_p = mg sin \theta$

where

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration due to gravity

$\theta=33.0^{\circ}$ is the angle of the incline

This force is directed down along the slope

- The frictional force, given by

$F_f = - \mu mg cos \theta$

where

$\mu$ is the coefficient of kinetic friction

According to Newton's second law, the resultant of the forces is equal to the product between mass and acceleration:

$W-F_f = ma\\mg sin \theta - \mu mg cos \theta = ma$

Solving for $\mu$ , we find

$\mu = \frac{g sin \theta - a}{g cos \theta}=\frac{(9.8 m/s^2)sin 33.0^{\circ} - 1.23 m/s^2}{(9.8 m/s^2) cos 33.0^{\circ}}=0.50$

(c) 12.3 N

The frictional force acting on the block is given by

$F_f = \mu mg cos \theta$

where

$\mu = 0.50$ is the coefficient of kinetic friction

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=33.0^{\circ}$ is the angle of the incline

Substituting, we find

$F_f = (0.50)(3.00 kg)(9.8 m/s^2) cos 33.0^{\circ} =12.3 N$

(d) 6.26 m/s

The motion along the surface of the incline is an accelerated motion, so we can use the following SUVAT equation

$v^2 - u^2 = 2ad$

where

v is the final speed of the block

u = 0 is the initial speed

a = 1.23 m/s^2 is the acceleration

d = 2.00 m is the distance covered

Solving the equation for v, we find the speed of the block after 2.00 m:

$v=\sqrt{u^2 + 2ad}=\sqrt{0^2+2(9.8 m/s^2)(2.00 m)}=6.26 m/s$

5 0

3 years ago